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Katena32 [7]
2 years ago
13

If f(x) = x³ +7x²-x and g(x)=x²-3, What is the degree of g(f(x))? a)2 b)3 c)6 d)8

Mathematics
2 answers:
andrezito [222]2 years ago
5 0

Answer:

<u>c) 6</u>

Step-by-step explanation:

Given :

⇒ f(x) = x³ + 7x² - x

⇒ g(x) = x² - 3

===============================================================

Finding the degree of g(f(x)) :

⇒ Degree of f(x) = 3

⇒ Degree of g(x) = 2

⇒ Therefore, degree of g(f(x)) = degree of f(x) × degree of g(x)

⇒ Degree of g(f(x)) = 3 × 2

⇒ Degree of g(f(x)) = <u>6</u>

MrMuchimi2 years ago
5 0
  • g(f(x))
  • g(x³+7x²-x)
  • (x³+7x²-x)²-3

Degree of g(f(x))

Use Pascal's law

  • 3×2
  • 6

Option C

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4 0
3 years ago
what are two practical products you could add to find 990 x 37 ; 297 693 2970 6930 69300 6330 29700
VMariaS [17]
First evaluate 990 x 37.
990 x 37 = 36630

Test the given numbers to find the pair that adds up to 36630.
Test 297.
The missing pair will be
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8 0
3 years ago
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3 years ago
How many integers between 360 and 630 are there such that they have odd number of divisors?
Kryger [21]

Answer:

7

Step-by-step explanation:

Concept to Know: "A number is a perfect square if and only if it has odd number of positive divisors "

Find all the squared values that lies between 360 and 630

360< 19², 20², 21², 22², 23², 24², 25² < 630

19², 20², 21², 22², 23², 24², and 25² are all the squared values that lies between 360 and 630. There are seven of those squared numbers so the answer is 7.

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