Question

J'K'L'M' is a translation of JKLM by vector (-6/2). What are the coordinates of K'? What are the coordinates of M'?

Answer 1

By applying the concept of rigid transformation and the equation of translation we conclude that the coordinates of points K' and M' are (-2, 3) and (-4, 1).

How to apply a translation to a point on a Cartesian plane

Rigid transformations are transformations applied onto geometric loci such that Euclidean distance is conserved at every point of the loci. Translations are an example of rigid transformations, whose formula is defined by the following expression:

$P'(x, y) = P(x, y) + \vec v$     (1)

Where:

• P(x, y) - Original point
• P'(x, y) - Resulting point
• $\vec v$ - Translation vector

If we know that K(x, y) = (4, 1), M(x, y) = (2, -1) and $\vec v = (-6, 2)$, then the coordinates of points K' and M' are:

Point K'

K'(x, y) = (4, 1) + (-6, 2)

K'(x, y) = (-2, 3)

Point M'

M'(x, y) = (2, -1) + (-6, 2)

M'(x, y) = (-4, 1)

By applying the concept of rigid transformation and the equation of translation we conclude that the coordinates of points K' and M' are (-2, 3) and (-4, 1).

To learn more on translations: brainly.com/question/17485121

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