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Temka [501]
3 years ago
12

Welp, the last one before the test

Mathematics
2 answers:
andrezito [222]3 years ago
3 0

Answer:

y=2x-3

Step-by-step explanation:

y=mx+c

m=gradient=

5-(-5)/4-(-1)

=10/5

=2

c=y intercept=-3

y=2x-3

bagirrra123 [75]3 years ago
3 0

Answer:

y = 2x - 3

Step-by-step explanation:

(4, 5) and (0, -3)

m=(y2-y1)/(x2-x1)

m=(-3-5)/(0-4)

m=(-8)/(-4)

m=2

y - y1 = m(x - x1)

y - 5 = 2(x - 4)

y - 5 = 2x - 8

y = 2x - 3

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Enter the values to complete the input/output table for the function.
Artist 52 [7]

Given function : 3x−6y=12.

We are given x :  −2     0    4.

We need to find the values of y's for x=-2, x=0 and x=4.

Plugging x=-2 in the given equation, we get

3(-2)−6y=12

-6 - 6y = 12.

Adding 6 on both sides, we get

-6+6 - 6y = 12+6

-6y = 18.

Dividing by -6 on both sides, we get

y= -3.

On the same way, plugging x=0.

3(0)−6y=12

-6y =12.

y=-2.

Plugging x=4,

3(4)−6y=12

12 -6y = 12.

Subtracting 12 on both sides.

12-12 -6y = 12-12

-6y=0

y=0.

Therefore,

<h3>x    −2   0   4</h3><h3>y ​    -3   -2  0</h3>
3 0
3 years ago
60 POINTSSSS Answer correctly please this depeneds on my dumb GRADE PLEASE
Maru [420]

Answer:

Option 4

Step-by-step explanation:

It's a geometric progression.

After t years,

500(1.1^t)

After 6 years,

500(1.1⁶) = 885.7805

4 0
3 years ago
What is the product?
ZanzabumX [31]

Answer:

The product is:

\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]

Step-by-step explanation:

For this problem you need to multiply the first row only for the two first column of the others matrix and get the desired result:

\left[\begin{array}{ccc}1&3&1\\-2&1&0\end{array}\right] \times \left[\begin{array}{cc}2&-2\\3&5\\4&1\end{array}\right]

1 \times 2 + 3 \times 3 + 1 \times -2 = 15

So the value of the element in the position a_{11} is 15

1 \times -2 + 3 \times 5 + 1 \times 1 = 14

So the value of the element in the position a_{12} is 14

Then with these two values you can determinate the result matrix.

\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]

3 0
2 years ago
An investment strategy has an expected return of 15 percent and a standard deviation of 9 percent. Assume investment returns are
IgorLugansk [536]

Answer:

68% of an investment earning a return between 6 percent and 24 percent.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 15

Standard deviation = 9

How likely is it to earn a return between 6 percent and 24 percent?

6 = 15 - 1*9

6 is one standard deviation below the mean

24 = 15 + 1*9

24 is one standard deviation above the mean

By the empirical rule, there is a 68% of an investment earning a return between 6 percent and 24 percent.

6 0
3 years ago
What is 0.11/5.973 please show work
german

Answer:

  0.0184162062615101289...

Step-by-step explanation:

In the attachment, the quotient is calculated "by hand" to 7 decimal places (6 significant figures). The quotient is a repeating decimal with a 180-digit repeat.

This is a good problem for your calculator.

5 0
3 years ago
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