Given that the triangle is a right angled triangle, to solve for x we shall use the Pythagorean theorem given by:
c^2=a^2+b^2
where:
c is the hypotenuse
a and b are the legs.
c=10
a=6
b=(x-6)
thus plugging the values in the equation and solving for x we get:
10^2=6^2+(x-6)^2
100=36+x^2-12x+36
100=x^2-12x+72
0=x^2-12x-28
factoring the above we get:
0=(x+2)(x-14)
hence
x=-2 or x=14
given that there is no negative distance then
x=14
thus the value of x is 14
H(x) = 0.15x - 0.19
p(x) = 0.29x - 0.16
(p · h)(-8) = (0.29(-8) - 0.16)(0.15(-8) - 0.19)
(p · h)(-8) = (-2.32 - 0.16)(-1.2 - 0.19)
(p · h)(-8) = (-2.48)(-1.39)
(p · h)(-8) = 3.4472
It is approximately equal to 3.
Answer:
in 13.95 years the senior class will have 100 students.
Step-by-step explanation:
P(h) = p(0.92)^t (equation for exponential change)
P(h) - population of highschool (or senior class) = 100
p - staring amount = 320
t = time in years
100 = 320(0.92)^t
1/3.2 = .92^t (divide both sides by 320)
log(1/3.2, .92) = t (log base 0.92 of 1/3.2 equals t)
13.9497 = t
C
the sum to infinity of a geometric series = 
where a is the first term and r the common ratio
= 
= 81 × 3 = 243
