Answer:
I'm not too sure which one you need, so choose what answer needs to go in the box!
JL= 44.5
JK=23.3
KL=23.3
Step-by-step explanation:
Since JK and KL are equal to eachother, we have to find the missing variable through them. You want to choose one side to have the variable number and the other side for the normal numbers. I can't really explain this next bit, so I'll show the math below:
V N
4x - 10.7 = 2x + 6.3
+10.7. +10.7
_________________
4x = 2x + 17
-2x -2x
2x = 17
So, once there is only one variable number and one normal number left, what do you do? You divide the variable by the number it's worth and carry the division to the normal number.
2x = 17
÷2. ÷2
_______
x = 8.5
So, 8.5 is our number we need. We then just insert it into all the equations to get the numbers.
4 × 8.5 = 34
34 - 10.7 = 23.3
Since JK and KL are equal, they are both 23.3.
5 × 8.5= 42.5
42.5 + 2 = 44.5
JL=44.5
I Believe I think it’s equal
9514 1404 393
Answer:
54.8 km
Step-by-step explanation:
The sketch and the applicable trig laws cannot be completed until we understand what the question is.
<u>Given</u>:
two boats travel for 3 hours at constant speeds of 22 and 29 km/h from a common point, their straight-line paths separated by an angle of 39°
<u>Find</u>:
the distance between the boats after 3 hours, to the nearest 10th km
<u>Solution</u>:
A diagram of the scenario is attached. The number next to each line is the distance it represents in km.
The distance (c) from B1 to B2 can be found using the law of cosines. We can use the formula ...
c² = a² +b² -2ab·cos(C)
where 'a' and 'b' are the distances from the dock to boat 1 and boat 2, respectively, and C is the angle between their paths as measured at the dock.
The distance of each boat from the dock is its speed in km/h multiplied by the travel time, 3 h.
c² = 66² +87² -2·66·87·cos(39°) ≈ 3000.2558
c ≈ √3000.2558 ≈ 54.77
The boats are about 54.8 km apart after 3 hours.
If they are asking you to rewrite the question, otherwise known as rephrasing it, you would write it from left to right! So...
z-6<u>></u>11 That's exactly how you would put it.
Answer:c
Step-by-step explanation: coochileman