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bixtya [17]
2 years ago
5

What is the slope of a line that is perpendicular to the line y = x 4? the slope of the line is .

Mathematics
1 answer:
SIZIF [17.4K]2 years ago
7 0

Answer:-1/4

Step-by-step explanation:

Take the negative of the reciprocal for perpendicular lines. In the case of no slope (y=number) replace y with x

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The area of a triangular Block is 100 square inches. If the base of the triangle is twice the height,how long are the base and t
timurjin [86]
Area = 1/2 base x height
Area = 1/2 (2 x height) x height
Area = height x height
Area = height^2
100 = height^2
height = SquareRoot(100)
Height = 10
Base = 2 x height = 2 x 10 = 20
8 0
3 years ago
Find B if the graph of the equation 3x=By+2 is perpendicular to the graph of 3y=-2x+4.
BigorU [14]

Answer:

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Step-by-step explanation:

4 0
3 years ago
HELP! I NEED MORE THAN 5 SENTENCES!!
Ksenya-84 [330]

Answer:

I would assess what type of learner my student was by seeing which form of teaching they respond best to. I would try to cover all 7 types of learning by going through different examples. I would lead by explaining the concept and then start to work through at least 3 examples. I would then ask them to finish certain parts and eventually watch them work one out on their own. One of the key things I would make sure to do is personalize the learning experience. I would offer stories and situations that they may be able to relate to or remember when completing the problem.

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3 years ago
Make g the subject of the formula <img src="https://tex.z-dn.net/?f=w%3D7-%5Csqrt%7Bg%7D" id="TexFormula1" title="w=7-\sqrt{g}"
dolphi86 [110]

Answer:

Step-by-step explanation:

\sqrt{g} = 7-w

(\sqrt{g} )^2 = (7-w)^2

g = (7-w)^2

3 0
3 years ago
A standard piece of paper is 0.05 mm thick. Let's imagine taking a piece of paper and folding the paper in half multiple times.
tatyana61 [14]

Answer:

(a)g(n)=0.05\cdot 2^n

(b)g^{-1}(n)=\log_{2}20g(n)

(c)43 times

Step-by-step explanation:

<u>Part A</u>

The paper's thickness = 0.05mm

When the paper is folded, its width doubles (increases by 100%).

The thickness of the paper grows exponentially and can be modeled by the function:

g(n)=0.05(1+100\%)^n\\\\g(n)=0.05\cdot 2^n

<u>Part B</u>

<u />g(n)=0.05\cdot 2^n\\2^n=\dfrac{g(n)}{0.05}\\ 2^n=20g(n)\\$Changing to logarithm form, we have:\\\log_{2}20g(n)=n\\$Therefore:\\g^{-1}(n)=\log_{2}20g(n)<u />

<u />

<u>Part C</u>

If the thickness of the paper, g(n)=384,472,300,000 mm

Then:

g^{-1}(n)=\log_{2}20g(n)\\g^{-1}(n)=\log_{2}20\times 384,472,300,000\\=\dfrac{\log 20\times 384,472,300,000}{\log 2} \\g^{-1}(n)=42.8 \approx 43\\n=43

You must fold the paper 43 times to make the folded paper have a thickness that is the same as the distance from the earth to the moon.

3 0
3 years ago
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