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wlad13 [49]
2 years ago
13

What kind of shape is this ?

Mathematics
2 answers:
Lemur [1.5K]2 years ago
8 0
Prism because it is a three dimensional shape
Stells [14]2 years ago
5 0

Answer:

prism

Step-by-step explanation:

when all the sides are joined, it will reveal the shape to become a prism.

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The approximate distance between J and K is units. The approximate distance between K and L is units. The approximate distance b
Dima020 [189]
Count the distance d, which gives you 7.

Use Pythogarean theorem to find c:
{a}^{2}  +  {b}^{2}   =   {c}^{2}
Plug in the numbers:
{4}^{2}  +  {3}^{2}  =  {c}^{2}   \\  \\ = 16 + 9  \\  \\ = 25 \\  \\ c =  \sqrt{25}  = 5
c is 5.

Same thing with g:
{e}^{2}  +  {f}^{2}  =  {g}^{2}  \\  \\    {g}^{2} = {4}^{2}  +  {4}^{2}  \\  \\  = 16 + 16 \\  \\  = 32 \\  \\ g =  \sqrt{32} = 4 \sqrt{2}  = 5.66
g equals 5.66.

7 0
3 years ago
(3ab-3a-8)-(-4ab-8) find the difference
sdas [7]
3ab - 3a - 8 + 4ab + 8
7ab -3a
6 0
2 years ago
On a coordinate plane, a square has points A (negative 5, 2), B (1, 2), C (negative 4, 1), and D (negative 5, negative 4).
Mars2501 [29]

Answer:

-6

Step-by-step explanation: dont know, did math. this is the answer on edge

6 0
3 years ago
Read 2 more answers
1. A square ABCD has the vertices A(n, n), B(n, -n), C(-n, -n), and D(-n, n). Which vertex is in Quadrant III?
andrew-mc [135]

The four quadrants and the sign of coordinates is given as follows:

Quadrant I : (n, n ) both x and y positive.

Quadrant II : ( -n,n) = x negative and y positive.

Quadrant III : ( -n,-n) = both x and y negative.

Quadrant IV: (n, -n) = x positive and y negative.

So Based on the above concept , we can say that vertex C (-n,-n) has both x and y negative and so it lies in quadrant III.

Answer is Vertex C (-n,-n)

5 0
3 years ago
Read 2 more answers
The mass of the sun is 21.3525×102921.3525×1029 kg. the mass of mercy is 328.5×1021328.5×1021 kg.how many times larger is the ma
Liono4ka [1.6K]
This is basically a simple problem to understand. The only thing that needs to be done is to divide the mass of the sun by the mass of mercury. It will give the required result.

Number of times the mass of sun is greater than
the mass of mercury =  21.3525×102921.3525×1029/<span>328.5×1021328.5×1021
                                  = </span><span>7.1783629e+15
I hope that this is the answer that you were looking for and it has come to your great help.</span>
8 0
3 years ago
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