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ollegr [7]
3 years ago
11

If AC = 20 centimeters, and BC = 16 centimeters, which does AB equal?

Mathematics
1 answer:
Anna11 [10]3 years ago
8 0

Answer:

The answer is B. 12 cm

Step-by-step explanation:

ABC is a right triangle

AB and BC are the legs and AC is the hypotenuse.

The Pythagorean theorem a^2 + b^2 = c^2 can be manipulated to solve for a and get 12.

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( -20 , 14 ) and ( 30, 18)<br> Slope, Explanation needed please HELPPPPPP
Morgarella [4.7K]

Answer: 2/25

Step-by-step explanation:

The formula to find the slope is (y2-y1)/(x2-x1)

If you plug in the numbers, you get (18-14)/(30-(-20))

Solve the expression and you get 4/50 = 2/25

So your answer is 2/25

6 0
2 years ago
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What is the name of the shape of the graph of a quadratic function?
dimaraw [331]
Is this a multiple choice or no
6 0
3 years ago
Which point-slope equation represents a line that passes through (3,-2) with a slope of -4/5?
Viefleur [7K]

Answer:

y + 2 = -4/5 (x - 3)

Step-by-step explanation:

y - y1 = m (x - x1). Put in your points for y1 and x1, and always remember to flip your signs.

unfortunately, I don't know why that isn't one of your answers, so sticking with the positive 2 I would choose y+2=- (- 3) if I were you. Looks like the -4/5 disappeared somehow?

Hope this helps

8 0
2 years ago
What is 0 + y when y = -11
Mashutka [201]

when y = -11, 0 + y is equal to -11.

the question is asking us to add 0 to the given value of y. the given value of y is -11, so place -11 into 0 + y and you get 0 + -11. since you are adding zero, you are making no changes to the y value, so it stays at -11.

<em>hope this helps and have a great day!</em>

3 0
3 years ago
Read 2 more answers
A simple random sample of size nequals10 is obtained from a population with muequals68 and sigmaequals15. ​(a) What must be true
valentina_108 [34]

Answer:

(a) The distribution of the sample mean (\bar x) is <em>N</em> (68, 4.74²).

(b) The value of P(\bar X is 0.7642.

(c) The value of P(\bar X\geq 69.1) is 0.3670.

Step-by-step explanation:

A random sample of size <em>n</em> = 10 is selected from a population.

Let the population be made up of the random variable <em>X</em>.

The mean and standard deviation of <em>X</em> are:

\mu=68\\\sigma=15

(a)

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Since the sample selected is not large, i.e. <em>n</em> = 10 < 30, for the distribution of the sample mean will be approximately normally distributed, the population from which the sample is selected must be normally distributed.

Then, the mean of the distribution of the sample mean is given by,

\mu_{\bar x}=\mu=68

And the standard deviation of the distribution of the sample mean is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{15}{\sqrt{10}}=4.74

Thus, the distribution of the sample mean (\bar x) is <em>N</em> (68, 4.74²).

(b)

Compute the value of P(\bar X as follows:

P(\bar X

                    =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the value of P(\bar X is 0.7642.

(c)

Compute the value of P(\bar X\geq 69.1) as follows:

Apply continuity correction as follows:

P(\bar X\geq 69.1)=P(\bar X> 69.1+0.5)

                    =P(\bar X>69.6)

                    =P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{69.6-68}{4.74})

                    =P(Z>0.34)\\=1-P(Z

Thus, the value of P(\bar X\geq 69.1) is 0.3670.

7 0
3 years ago
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