If you look closely at the graph 10 dollars are the price of 5 tickets and so we could use 2T = P as a expression and so if you plug 20 into T it would be 2(20)=P and it would become a evident 40=P as the answer (40)
Answer:
46 packages
Step-by-step explanation:
2 7/8= 23/8= 46/16...THUS SINCE SHE IS MAKING 1/16 POUND PACKAGES, SHE CAN MAKE 46 PACKAGES
To find the derivative of this function, there is a property that we should know called the Constant Multiple Rule, which says:
![\dfrac{d}{dx}[cf(x)] = cf'(x)](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%7D%7Bdx%7D%5Bcf%28x%29%5D%20%3D%20cf%27%28x%29)
(where 
is a constant)
Remember that the derivative of 
is 
. However, you may notice that we are finding the derivative of 
, not 
. So, we are going to have to use the chain rule. To complete the chain rule for the derivative of a trigonometric function (in layman's terms) is basically the following: First, complete the derivative of the trig function as you would if what was inside the trig function is 
. Then, take the derivative of what's inside of the trig function and multiply it by what you found in the first step.
Let's apply that to our problem. Right now, I am not going to worry about the 
at the front of the equation, since we can just multiply it back in at the end of our problem. So, let's examine 
. We see that what's inside the trig function is 
, which has a derivative of 2. Thus, let's first find the derivative of as if was just and then multiply it by 2.
The derivative of would first be 
. Multiplying it by 2, we get our derivative of 
. However, don't forget to multiply it by the that we removed near the beginning. This gives us our final derivative of .
Remember that we now have to find the derivative at the given point. To do this, simply "plug in" the point into the derivative using the x-coordinate. This is shown below:
![-\cot[2(\dfrac{\pi}{4})]\csc[2(\dfrac{\pi}{4})]](https://tex.z-dn.net/?f=-%5Ccot%5B2%28%5Cdfrac%7B%5Cpi%7D%7B4%7D%29%5D%5Ccsc%5B2%28%5Cdfrac%7B%5Cpi%7D%7B4%7D%29%5D)
Our final answer is 0.
For solving of the area of a square pyramid, we can use the formula below:
A=a²+2a sqrt (a²/4 +h²)
where s for the slant height, r for the a/2, where a is the side length and h for the height
Substitute the values,
A=40²+(2*40) SQRT (40²/4 +21²)
A=3920
The answer is 3920 for the area of the square pyramid.
