This is Algebra btw.
1 answer:
<h2>Step-by-step explanation:</h2>
Given equations;
y₁ = 3x - 8 -------------------(i)
y₂ = 0.5x + 7 --------------------(ii)
To fill the table, substitute the values of x into equations (i) and (ii)
=> At x = 0
y₁ = 3(0) - 8 = -8
y₂ = 0.5(0) + 7 = 7
=> At x = 1
y₁ = 3(1) - 8 = -5
y₂ = 0.5(1) + 7 = 7.5
=> At x = 2
y₁ = 3(2) - 8 = -2
y₂ = 0.5(2) + 7 = 8
=> At x = 3
y₁ = 3(3) - 8 = 1
y₂ = 0.5(3) + 7 = 8.5
=> At x = 4
y₁ = 3(4) - 8 = 4
y₂ = 0.5(4) + 7 = 9
=> At x = 5
y₁ = 3(5) - 8 = 7
y₂ = 0.5(5) + 7 = 9.5
=> At x = 6
y₁ = 3(6) - 8 = 10
y₂ = 0.5(6) + 7 = 10
=> At x = 7
y₁ = 3(7) - 8 = 13
y₂ = 0.5(7) + 7 = 10.5
=> At x = 8
y₁ = 3(8) - 8 = 16
y₂ = 0.5(8) + 7 = 11
=> At x = 9
y₁ = 3(9) - 8 = 19
y₂ = 0.5(9) + 7 = 11.5
=> At x = 10
y₁ = 3(10) - 8 = 22
y₂ = 0.5(10) + 7 = 12
The complete table is attached to this response.
(ii) To find the solution of the system of equations using the table, we find the value of x for which y₁ and y₂ are the same.
As shown in the table, that value of <em>x = 6</em>. At this value of x, the values of y₁ and y₂ are both 10.
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Answer:
Option (C)
Option (C)
Option (A)
Step-by-step explanation:
Part A.
Frank's walking speed can be represented by the equation.
Equation representing the speed is,
y = 85x
Therefore, walking speed of Frank = 85 meters per minute.
Option (C) will be the answer.
Part B.
Distance walked over the time by Jeffrey is given by the graph attached.
Equation for the speed will be,
y =
y = 80x
Therefore, walking speed of Jeffrey = 80 meters per minute
Difference in the speed of Frank and Jeffrey = 85 - 80 = 5 meters per minute.
Jeffery walks 5 meters per minute slower than Frank.
Option (C) will be the answer.
Part (C)
Distance traveled by Frank in 16 minutes,
y = 85(16) = 1360 meters
Time taken to travel the same distance by Jeffrey will be,
1360 = 80x
x = meters per minute
Option (A) will be the answer.