slope = 13
the slope of the tangent is f'( 4)
given f(x) = x² + 5x , then f'(x) = 2x + 5
and f'(4) = ( 2 × 4 ) + 5 = 13
Most likely to be letter C
For this case we have the following functions:
f (x) = 3x + 4
g (x) = 2 ^ x - 1
The intersection with the y axis of the original functions is:
f (0) = 3 (0) + 4 = 0 + 4 = 4
g (0) = 2 ^ 0 - 1 = 1 - 1 = 0
The transformations that must be applied so that they have the same intersection with the y axis are:
f (x) - 3
g (x) + 1
Answer:
f (x) - 3
g (x) + 1
option 1
Answer:
but I will not let him die
Step-by-step explanation:
v I I 56r6eyci fee will notify include his
Answer:
5x=25
Step-by-step explanation:
if you need the answer
5x5=25
5+5+5+5+5=25
