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4 years ago

Prove the identity (n-5)^2 - (6n-35)=(n-10)(n-6)

Mathematics

1 answer:

elena-14-01-66 [18.8K]4 years ago

7 0

Answer:

(n-5)^2 - (6n-35)=(n-10)(n-6)

-----------

n²-10n+25-6n+35 =
n²-16+60 = n²- 10n - 6n + 60 =
n(n-10) - 6(n-10) =
(n-10)(n-6)

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