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Tanzania [10]
2 years ago
11

Can someone help me with this

Mathematics
1 answer:
Pavlova-9 [17]2 years ago
8 0

Step-by-step explanation:

after I answered the other one(s), you should be really able to do this yourself.

it is precisely the same method and formula just with different numbers.

what's the problem now ?

y = -16x² + 247x + 141

we assume, the ground is at 0 ft.

so, we need to solve

0 = -16x² + 247 x + 141

the general solution for such quadratic equations is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

a = -16

b = 247

c = 141

x = (-247 ± sqrt(247² - 4×-16×141))/(2×-16) =

= (-247 ± sqrt(61009 + 9024))/-32 =

= (-247 ± sqrt(70033))/-32

x1 = (-247 + 264.6374879...)/-32 = -0.551171497... s

x2 = (-247 - 264.6374879...)/-32 = 15.9886715... s

again, the negative solution for time did not make any sense, so, x2 is our solution.

the rocket will hit the ground after about 15.99 seconds.

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Answer:

Step-by-step explanation:

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and you cut it in half.

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2 years ago
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What is the approximate circumference of a circle with a diameter of 500 kilometers? Use π ≈ 3.14.. . A.. 785 kilometers. . B..
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4 years ago
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Please I need help with this problem
DochEvi [55]

Answer: shorter: 24 longer: 41

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4 0
3 years ago
A study of immunizations among school‑age children in California found that some areas had rates of unvaccinated school‑age chil
Rom4ik [11]

Answer:

Probability that none of the 20 children in such a classroom would be unvaccinated is 0.055.

Step-by-step explanation:

We are given that a classroom of 20 children in one such area where 13.5% of children are unvaccinated.

If there are no siblings in the classroom, we are willing to consider the vaccination status of the 2020 unrelated children to be independent.

The above situation can be represented through binomial distribution;

P(X=r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,......

where, n = number of trials (samples) taken = 20 children

            r = number of success = none of the 20 children

            p = probability of success which in our case is probability that

                   children are unvaccinated, i.e; p = 13.5%

<u><em>Let X = Number of children that are unvaccinated</em></u>

So, X ~ Binom(n = 20, p = 0.135)

Now, Probability that none of the 20 children in such a classroom would be unvaccinated is given by = P(X = 0)

           P(X = 0)  =  \binom{20}{0} \times 0.135^{0} \times (1-0.135)^{20-0}

                          =  1\times 1 \times 0.865^{20}

                          =  0.055

<em>Hence, the probability that none of the 20 children in such a classroom would be unvaccinated is 0.055.</em>

8 0
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Answer:

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