We have been given that Judy’s brother Sam has a collection of 96 comic books. We have been asked to find the 10 ways Sam could divide his comic books into equal groups.
This can be done as follows:
96 can be written as 
. Thus, we can either have 2 groups of 48 comics or 48 groups of 2 comics. As we can see we have 2 ways to divide the comic books in equal groups.
Likewise, 96 can also be written as 
. Here, we can similarly see that we can either have 3 groups of 32 comics or 32 groups of 3 comics. As we can again see we have 2 more ways to divide the comic books in equal groups, taking the total number of ways to 4.
Continuing in this manner we will see that we can have 4 groups of 24 or 24 groups of 4, 6 groups of 16 or 16 groups of 6 and lastly 12 groups of 8 or 8 groups of 12 comic books, thus taking the count to a <u>total of 10 ways</u> in which Sam can divide his comic books into equal groups.
Our question has been answered.
Answer:
A) X + Y = 12
B) 10Y + x = 10x + Y -18
B) 9Y = 9x -18 multiplying A) by -9
A) -9Y = 9x - 72 adding A and B we get
0 = 18x -90
x = 5
The number is 75
Double-Check
7 + 5 = 12
75 -57 = 18
Step-by-step explanation:
Hey there :)
3 ( 2t + 1 )
We use what is called the distributive property to get rid of the parenthesis
We multiply the term outside the parenthesis by all terms inside
3 ( 2t ) + 3 ( 1 )
6t + 3 → Your answer
Answer:
B.) -⅔
Step-by-step explanation:
Subtract each variable
y¹-y
x¹-x
-2-4 = -6
4-(-5) = 9 -6/9 = -⅔
