There are 4 teams in total and each team has 7 members. One of the team will be the host team.
Tournament committee will be made from 3 members from the host team and 2 members from each of the three remaining teams. Selecting the members for tournament committee is a combinations problem. We have to select 3 members out 7 for host team and 2 members out of 7 from each of the remaining 3 teams.
So total number of possible 9 member tournament committees will be equal to:

This is the case when a host team is fixed. Since any team can be the host team, there are 4 possible ways to select a host team. So the total number of possible 9 member tournament committee will be:

Therefore, there are 2917215 possible 9 member tournament committees
Answer:
22
Step-by-step explanation:
Hello!
You put 16 in for u and 4 in for t
v = (16) + 10(4)
Multiply
v = 16 + 40
Add
v = 56
The answer is v = 56
Hope this helps!
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Answer:
First angle = 30°
Second angle = 60°
Third angle = 90°
Step-by-step explanation:
x + y + z = 180
y + z = 5x
z = y + 30
then:
y + (y+30) = 5x
2y + 30 = 5x
x = (2y+30)/5
then:
x + y + z = 180
{(2y+30)/5} + y + y+30 = 180
{(2y+30)/5} + 2y + 30 = 180
{(2y+30)/5} = 180 - 30 - 2y
{(2y+30)/5} = 150 - 2y
2y+30 = 5(150-2y)
2y+30 = 5*150 + 5*-2y
2y+30 = 750 - 10y
2y + 10y = 750 - 30
12y = 720
y = 720/12
y = 60°
x = (2y+30)/5
x = (2*60 + 30)/5
x = (120+30)/5
x = 150/5
x = 30°
z = y + 30
z = 60 + 30
z = 90°
Check:
x + y + z = 180°
30° + 60° + 90° = 180°