All categories

3 years ago

If you multiply two integers, you'll always get an integer. True or false? EXPLAIN?

Mathematics

1 answer:

agasfer [191]3 years ago

6 0

Answer:

True because integers are whole numbers so if u multiply two whole numbers u will get an whole number not a fraction or decimal.

Step-by-step explanation:

2x2=4

6x6=36

12x5=60

You might be interested in

NEED THIS DONE ASAP!! Thank you!!

Dovator [93]

Answer:

x=40

Step-by-step explanation:

Angle Formed by Two Secants= 1/2(DIFFERENCE of Intercepted Arcs)

x = 1/2(120-40)

x = 1/2(80)

x = 40

7 0

2 years ago

Read 2 more answers

A trout lurking 32 cm below the surface of a lake spies an insect flying 17cm above the lake. How many centimeters would the tro

Bumek [7]

Answer:

The Trout will have to jump 49 cm in order to catch the insect

Step-by-step explanation:

Here, we want to calculate the distance the Trout has to jump in order to catch the Insect

To calculate this, we need to know the difference in the distances

From what we have, the Trout is 32 cm below the surface while the Insect is 17 cm above the surface of the lake

The difference in height which will represent the distance that the Trout has to jump to catch the insect will be ;

17 + 32 = 49 cm

3 0

2 years ago

23. Two coins are tossed. Alan gets a point if the coins match and Sondra gets a point if they do not match.

Keith_Richards [23]

Answer:

C. They have the same chance of winning.

Step-by-step explanation:

Probability (2 tails) = 1/2 * 1/2 = 1/4

Probability( 2 heads = 1/2 * 1/2 = 1/4.

Therefore the Probability they match = 1/4 + 1/4 = 1/2.

The probability of they don't match = 1 - 1/2 = 1/2 because all probabilities add up to 1. There are only 4 possible results and their probabilities must add up to 1.

5 0

3 years ago

Read 2 more answers

Expand (2x+2)^6<br> How would you find the answer using the binomial theorem?

Yanka [14]

Answer:

Step-by-step explanation:

$\displaystyle\\\sum\limits _{k=0}^n\frac{n!}{k!*(n-k)!}a^{n-k}b^k .\\\\k=0\\\frac{n!}{0!*(n-0)!}a^{n-0}b^0=C_n^0a^n*1=C_n^0a^n.\\\\ k=1\\\frac{n!}{1!*(n-1)!} a^{n-1}b^1=C_n^1a^{n-1}b^1.\\\\k=2\\\frac{n!}{2!*(n-2)!} a^{n-2}b^2=C_n^2a^{n-2}b^2.\\\\k=n\\\frac{n!}{n!*(n-n)!} a^{n-n}b^n=C_n^na^0b^n=C_n^nb^n.\\\\C_n^0a^n+C_n^1a^{n-1}b^1+C_n^2a^{n-2}b^2+...+C_n^nb^n=(a+b)^n.$

$\displaystyle\\(2x+2)^6=\frac{6!}{(6-0)!*0!} (2x)^62^0+\frac{6!}{(6-1)!*1!} (2x)^{6-1}2^1+\frac{6!}{(6-2)!*2!}(2x)^{6-2}2^2+\\\\ +\frac{6!}{(6-3)!*3!} (2a)^{6-3}2^3+\frac{6!}{(6-4)*4!} (2x)^{6-4}b^4+\frac{6!}{(6-5)!*5!}(2x)^{6-5} b^5+\frac{6!}{(6-6)!*6!}(2x)^{6-6}b^6. \\\\$

$(2x+2)^6=\frac{6!}{6!*1} 2^6*x^6*1+\frac{5!*6}{5!*1}2^5*x^5*2+\\\\+\frac{4!*5*6}{4!*1*2}2^4*x^4*2^2+ \frac{3!*4*5*6}{3!*1*2*3} 2^3*x^3*2^3+\frac{4!*5*6}{2!*4!}2^2*x^2*2^4+\\\\+\frac{5!*6}{1!*5!} 2^1*x^1*2^5+\frac{6!}{0!*6!} x^02^6\\\\(2x+2)^6=64x^6+384x^5+960x^4+1280x^3+960x^2+384x+64.$