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olasank [31]
2 years ago
6

What is the least common denominator of 3, x, and x?

Mathematics
1 answer:
sergiy2304 [10]2 years ago
7 0

Answer:

Step-by-step explanation:

LCD

you have 1 x not 2.

Suppose you have

y/3 + 3y/x + 7y / x

Unless there is something different about the question, you need only 1 x. The other one get's absorbed.

Answer: LCM = 3 * x

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A pole that is 3.5m tall casts a shadow that is 1.47m long. At the same time, a nearby tower casts a shadow that is 42.75m long.
Sonja [21]

Answer:

Therefore the height of the tower is 101.79 m.

Step-by-step explanation:

The ratio of the height of an object to the shadow of the object is always constant at certain time.

\frac{\textrm{The height of object}}{\textrm{The  shadow of the object}}= constant

\Rightarrow \frac{h_1}{s_1}=\frac{h_2}{s_2}

Given that,the length of the pole is 3.5 m and it casts a shadow that is 1.47 m long.

The length of shadow that castes by a tower is 42.75 m long.

Here h₁= 3.5 m, s₁=1.47 m, h₂= ? and s₂=42.75 m

\therefore \frac {3.5}{1.47}=\frac{h_2}{42.75}

⇒3.5 ×42.75 = h₂× 1.47

\Rightarrow h_2=\frac{3.5 \times 42.75}{1.47}

⇒h₂ = 101.79 m (approx)

Therefore the height of the tower is 101.79 m.

6 0
3 years ago
Mary has rehearsed her ballet solo for five and a half hours. A week from now, she wants to have rehearsed at least a total of n
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The answer to this problem is 2
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An object is launched at 28 meters per second (m/s) from a 336-meter tall platform. The equation for the object's height s at ti
kondaur [170]

Answer:343 m

Step-by-step explanation:

Given

launch velocity of object is u=28\ m/s

height of Platform h=336\ m

height of object is given by

s(t)=-7t^2+14t+336

For maximum height velocity of object is zero

i.e. \frac{ds}{dt}=0

\frac{ds}{dt}=-14t+14+0=0

t=\frac{14}{14}=1\ s

Therefore after 1 sec object achieves maximum height

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s(1)=343\ m

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The answer of this equation is 8cm I did the math
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12 yards +14 feet by 2
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25 feet

Step-by-step explanation:

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