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Bumek [7]
2 years ago
8

The sum of two numbers is 27. One number is 2 times as large as the other. What are the numbers?

Mathematics
2 answers:
Alex2 years ago
6 0

Answer:

9 and 18

Step-by-step explanation:

x+y=27\\x=2y\\2y+y=27\\3y=27\\y=27/3=9\\x=27-9=18

masya89 [10]2 years ago
5 0

Answer: <em>Please note the number of the order may differ.</em>

n_1  = 18

n_2 = 9

Step-by-step explanation:

     We will write mathematical equations to represent the situation. Let n_1 be the first number and n_2 be the second.

-> The sum of two numbers is 27.

n_1 + n_2 = 27

-> One number is 2 times as large as the other.

n_1  = 2 * n_2

     Now, we will solve it as a system of equations.

n_1 + n_2 = 27

(2 * n_2) + n_2 = 27

3 * n_2 = 27

n_2 = 9

-----------

n_1  = 2 * n_2

n_1  = 2 * (9)

n_1  = 18

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Read 2 more answers
A trucking company uses matrix A , shown below, to represent the driving time in hours for 6 trucking routes. A = [ 4 6 8 ]
zepelin [54]

Each element of the matrix are multiplied by the scalar to form a matrix of

same size as the original matrix in matrix scalar multiplication.

  • 60 \cdot A = \left[\begin{array}{ccc}240\4&360&480\\360&480&600\end{array}\right]

Reasons:

The matrix <em>A</em> is presented as follows;

A = {\left[\begin{array}{ccc}4&6&8\\6&8&10\end{array}\right]}

Using the multiplication of a matrix and a scalar, we have;

60 \cdot A = 60 \cdot  \left[\begin{array}{ccc}4&6&8\\6&8&10\end{array}\right] =  \left[\begin{array}{ccc}60 \times 4&60 \times 6&60 \times 8\\60 \times 6&60 \times 8&60 \times 10\end{array}\right] = \left[\begin{array}{ccc}\mathbf{240}&\mathbf{360}&\mathbf{480}\\\mathbf{360}&\mathbf{480}&\mathbf{600}\end{array}\right]

Therefore;

60 \cdot A = \left[\begin{array}{ccc}240\4&360&480\\360&480&600\end{array}\right]

Learn more about matrices here:

brainly.com/question/14296012

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3 years ago
In a call center that stays open all the time, calls arrive as a poisson process with a mean rate of 0.3 complaints per hour.(a)
DENIUS [597]

The probability the 51st call arriaves within 150hours is 0.0431, the probability the next call arrives within the next 2 hours 0.5488, the probability the sum of these 50 numbers is less than 356 is 0.4165.

Data;

  • Mean rate = 0.3
  • x = 50
  • standard deviation = ?

<h3>Poission Rule</h3>

Using poission formula,

P(x=x) = \frac{e^-^\lambda - \lambda^x}{x!}\\\lambda = 0.3 per minute

Let's substitute the values into the formula.

For 50 calls in 150 hours

For 150 hours = x = 0.3 * 150 = 45

p(x=50) = \frac{e^-^4^5 * 45^5^0}{50!} = 0.0431

b)

The probability the next call arrives after 2 hours.

\lambda = 0.3 * 2 = 0.6\\p(x=0) = \frac{e^-^0^.^6 * 0.6^0}{0!} = 0.5488

c)

The number of calls recieved each day is recorded for 50 consecutive days.

for 50 days;

\lambda = 0.3 * 50 * 24 = 360

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The standard deviation is given as

S.D = \sigma =\sqrt{360} = 18.974\\

The probability the sum of these 50 number is less than 356 is

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