Question

The sum of two numbers is 27. One number is 2 times as large as the other. What are the numbers?

Answer 1

Answer:

9 and 18

Step-by-step explanation:

$x+y=27\\x=2y\\2y+y=27\\3y=27\\y=27/3=9\\x=27-9=18$

Answer 2

Answer: Please note the number of the order may differ.

$n_1$  = 18

$n_2$ = 9

Step-by-step explanation:

     We will write mathematical equations to represent the situation. Let $n_1$ be the first number and $n_2$ be the second.

-> The sum of two numbers is 27.

$n_1$ + $n_2$ = 27

-> One number is 2 times as large as the other.

$n_1$  = 2 * $n_2$

     Now, we will solve it as a system of equations.

$n_1$ + $n_2$ = 27

(2 * $n_2$) + $n_2$ = 27

3 * $n_2$ = 27

$n_2$ = 9

-----------

$n_1$  = 2 * $n_2$

$n_1$  = 2 * (9)

$n_1$  = 18