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Vlada [557]
3 years ago
12

PLEASE ASAP HELP WITH LETTER f

Mathematics
1 answer:
Softa [21]3 years ago
8 0
Ok so for Letter F the answer is going to be x=2 or y=-2 depending if you’re trying to find x or y.
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An object launched straight up at a speed of 29.4 meters per second has a height, h, in meters of h , t seconds after the object
Nostrana [21]

Answer:

h = 44.06 meters (maximum height)

the time the object takes to complete this whole path is 6 seconds, this is why the time at which the object reaches its maximum height will between 0 and 6 seconds

Step-by-step explanation:

To solve this question, we need to first recognize that this is a constant acceleration problem, specifically, it can be thought of as a projectile motion problem.

Recall, the equations of motion:

1) v^2 - v_0^2 = 2a(s - s_0)\\2) s = v_0^2  + \frac{1}{2} at^2\\3) v = v_0 + at

What do we already know?

  • v_0 = 29.4 ms^-1
  • The launch is straight up
  • a = -9.81 ms^-2 this is the gravitational acceleration g
  • s_0 = 0 m, since our reference point is at s = 0, (the ground)

We can use use the Eq(1):

we know that when any object is launched up, at maximum height its velocity is going to be zero, v = 0 ms^-2

v^2 - v_0^2 = 2a(s - s_0)\\0^2 - (29.4)^2 = 2(-9.81)(s- 0)\\s = 44.06 m

this is the maximum height!

Why does t have to between zero and six?

We can answer this using a bit visualization, if you think about the second equation

s = v_0 t - \frac{1}{2}at^2\\ s = 29.4t - 4.905t^2

this is the equation of the whole trajectory that object makes.

and if you solve this by making s = 0, you will get the times at which the object was at the ground. the times will be 0s and 5.99s.

so the amount of time the object takes to go through this whole path is 6 seconds and this why the object will only reach its maximum height in between this time interval.

hope this helps :)

5 0
3 years ago
the ratio of cars to trucks at an auto dealer is 3/2. if there are 144 cars at the dealership, how many trucks are there?​
lana [24]

Answer:

96

Step-by-step explanation:

for every 3 cars there is 2 trucks

If you have 144 cars then we divide 144 by 3 to get 48

That is not the answer though because that would be a 3/1 ratio

We then multiply 48 by 2 to get 96

5 0
3 years ago
Write an equation in terms of x. Solve the equation. Then find AB and BC.
Wittaler [7]
The answer is AB=7×+2
6 0
2 years ago
What is 125^2/3 in simplest form? and What is \sqrt[5]({-245} ) ^{5} in simplest form?
Natasha_Volkova [10]
{ 125 }^{ \frac { 2 }{ 3 }  }\\ \\ ={ \left( { 125 }^{ \frac { 1 }{ 3 }  } \right)  }^{ 2 }\\ \\ ={ \left( \sqrt [ 3 ]{ 125 }  \right)  }^{ 2 }\\ \\ ={ 5 }^{ 2 }\\ \\ =25

This is because:

{ a }^{ \frac { m }{ n }  }\\ \\ =\sqrt [ n ]{ { a }^{ m } }

Remember that:

5 x 5 x 5 = 125
5 0
3 years ago
Trapezia ABCD and PQRS are similar.<br> Find the area shaded in green.
avanturin [10]

The area shaded in green is 864 cm²

<h3>Similar figures</h3>

Similar figures, corresponding angles are congruent and the sides are ratio of each other. Therefore,

AB / PQ = CD / RS

30 / 10 = 24 / RS

30RS = 240

RS = 240 / 30

RS = 8 cm

let find the height of trapezium PQRS.

AB / PQ  = 36 / h

30 / 10 = 36 / h

30h = 360

h = 360 / 30

h = 12 cm

Therefore,

area of the green portion = area of ABCD - area of PQRS

<h3>Area of a trapezium</h3>
  • area = 1 / 2(a + b)h

Therefore,

area of ABCD = 1 / 2(24 + 30)36 =  1 / 2 (54)36 = 1944 / 2 = 972 cm²

area of PQRS = 1 / 2(10 + 8)12 = 1 / 2(18)12 = 216 / 2 = 108 cm²

Area of the green portion = 972 - 108 = 864 cm²

learn more on trapezium here: brainly.com/question/11961445

6 0
2 years ago
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