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2 years ago

Question 9 of 10

Mathematics

1 answer:

evablogger [386]2 years ago

4 0

Answer:

B and C

Step-by-step explanation:

vertical angles are angles that are opposite of each other when two lines cross. Vertical angles are congruent = they are equally large.

the angles listed in B and C are mirrored across either an imaginary or a directly visible line. and that makes them vertical angles.

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What is the approximate area of the shaded sector in the circle shown below

saul85 [17]

Answer:

D) 191

Step-by-step explanation:

The entire circle is 254.5, calculated by using this formula

$A=\pi r^{2} \\$

Only 3/4 of the circle is needed for the area, however, so you multiply your area by 0.75

3 0

3 years ago

How to draw to segments with the same midpoint

prisoha [69]

Just draw a line at the midpoint and a salon also if this helps OK

8 0

3 years ago

What is 6/4 simplified

Rashid [163]

Since this is an improper fraction, you simplify it into a mixed number.
4 goes into 6 1 time. 2 left left over, resulting in 1 2/4. Simplify that into
1 1/2

6 0

3 years ago

Read 2 more answers

a vehicle factory manufactures cars. The unit cost C (the cost in dollars to make each car) depends on the number of cars made.

timofeeve [1]

Answer:

8,567

Step-by-step explanation:

Given the cost function expressed as C(x)=0.7x^2- 462 x + 84,797

To get the minimum vaklue of the function, we need to get the value of x first.

At minimum value, x = -b/2a

From the equation, a = 0.7 and b = -462

x = -(-462)/2(0.7)

x = 462/1.4

x = 330

To get the minimum cost function, we will substitute x = 330 into the function C(x)

C(x)=0.7x^2- 462 x + 84,797

C(330)=0.7(330)^2- 462 (330)+ 84,797

C(330)= 76230- 152460+ 84,797

C(330) = 8,567

Hence the minimum unit cost is 8,567

7 0

3 years ago

Solve using the quadratic formula 3x^2+11x+5=0

storchak [24]

Answer:

$3x^2 + 11x + 5 = 0 : x = \frac{-11 + \sqrt{61} }{6} , x = \frac{-11 - \sqrt{61} }{6}$

Decimal:

$(x = -0.53162..., x = -3.13504...)$

Step-by-step explanation:

$3x^2+11x+5=0$

Solve with the quadratic formula:

For a quadratic equation of the form $ax^2+bx+c=0$ the solutions are:

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

For $a=3,\:b=11,\:c=5:\quad x_{1,\:2}=\frac{-11\pm \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3}$

$x=\frac{-11 + \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3} : \frac{-11 + \sqrt{61} }{6}$

$x=\frac{-11 - \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3} : \frac{-11 - \sqrt{61} }{6}$

The solutions to the quadratic equation are:

$x=\frac{-11+\sqrt{61}}{6},\:x=\frac{-11-\sqrt{61}}{6}$

Hope I helped. If so, may I get brainliest and a thanks?

Thank you, have a good day! =)

8 0

3 years ago