Answer:
| v | = 5,831
Step-by-step explanation:
Take the starting point.
In the graph you can see that the coordinates are (1,1)
Then it takes the final point that has the coordinates (4.6)
Now subtract the final coordinates - the initial coordinates
v = <
>
v = <4-1, 6-1>
v = <3, 5>
Then, by definition, the magnitude of the vector is:
![|v| = \sqrt{3^2 +5^2}\\\\|v| = \sqrt{9 + 25}\\\\|v| = \srqrt{34}\\\\|v| = 5.831](https://tex.z-dn.net/?f=%7Cv%7C%20%3D%20%5Csqrt%7B3%5E2%20%2B5%5E2%7D%5C%5C%5C%5C%7Cv%7C%20%3D%20%5Csqrt%7B9%20%2B%2025%7D%5C%5C%5C%5C%7Cv%7C%20%3D%20%5Csrqrt%7B34%7D%5C%5C%5C%5C%7Cv%7C%20%3D%205.831)
Answer:
<em>-14x+6</em>
Step-by-step explanation:
first, we distribute the -3.
-3(4x - 2) - 2x=-12x+6-2x
than, we conbide like terms
-12x+6-2x=-14x+6
60q+j=52
125q+j=65
multiply first equation by -1 and add to 2nd
-60q-j=-52
<u>125q+j=65 +</u>
65q+0j=13
65q=13
divde both sides by 65
q=0.2oz
sub back
when
60q+j=52
60(0.2)+j=52
12+j=52
minus 12 both sides
j=40
the jar is 40 ounces
Answer-
<em>The inverse of
is </em>
![\boxed{\boxed{y=\log_3 x}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cboxed%7By%3D%5Clog_3%20x%7D%7D)
<u>Solution-</u>
The given function is,
![y=3^x](https://tex.z-dn.net/?f=y%3D3%5Ex)
We can get the inverse by interchanging he variable x and y among themselves and then separating each variables.
So in the inverse would be,
![\Rightarrow x=3^y](https://tex.z-dn.net/?f=%5CRightarrow%20x%3D3%5Ey)
Taking log of both sides,
![\Rightarrow \log x=\log 3^y](https://tex.z-dn.net/?f=%5CRightarrow%20%5Clog%20x%3D%5Clog%203%5Ey)
As,
![\log a^b=b\times \log a](https://tex.z-dn.net/?f=%5Clog%20a%5Eb%3Db%5Ctimes%20%5Clog%20a)
Applying the same,
![\Rightarrow \log x=y\times \log 3](https://tex.z-dn.net/?f=%5CRightarrow%20%5Clog%20x%3Dy%5Ctimes%20%5Clog%203)
![\Rightarrow y=\dfrac{\log x}{\log 3}](https://tex.z-dn.net/?f=%5CRightarrow%20y%3D%5Cdfrac%7B%5Clog%20x%7D%7B%5Clog%203%7D)
As,
![\log_b a=\dfrac{\log a}{\log b}](https://tex.z-dn.net/?f=%5Clog_b%20a%3D%5Cdfrac%7B%5Clog%20a%7D%7B%5Clog%20b%7D)
Applying the same,
![\Rightarrow y=\log_3 x](https://tex.z-dn.net/?f=%5CRightarrow%20y%3D%5Clog_3%20x)
Therefore, the inverse of
is
.
Answer:
hypotenuse
Step-by-step explanation:
When you use the distance formula you are calculating the length of the hypotenuse of a right triangle.
When using the distance formula, you are making a right triangle whose hypotenuse connects two given points.