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Dimas [21]
2 years ago
12

Find the range of the function y=-x^2-3x when the domain is {-5,0,2}

Mathematics
1 answer:
umka21 [38]2 years ago
4 0

Answer: \{-10, 0 \}

Step-by-step explanation:

The range is the set of output values for the domain (the set of inputs).

  • When x=-5, y=-(-5)^{2}-3(-5)=-10.
  • When x=0, y=-0^{2}-3(0)=0.
  • When x=2, y=-2^{2}-3(2)=-10

So, the range is \boxed{\{-10, 0 \}}

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Eight thousandths of thirty five million
Andrej [43]
(Eight thousandths) * thirty five million =

two hundred eighty thousand

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3 years ago
Madison and Tyler each wrote an expression that is equivalent to 14.1 (19.8 + 7.6). The expressions they created are shown in th
diamong [38]

Answer: Tyler used the distributive property.

Step-by-step explanation:

For the expression:  

Madison wrote:  which is by commutative property of addition.

The commutative property of addition says that , for a,b be any real number

Tyler wrote: which is by distributive propery.

The distributive property says that , for a,b,c be any real numbers.

Hence, the last option is correct.

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3 years ago
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4.4 + (4 × 14 + 8.6)
Sedaia [141]

4.4 + (4 × 14 + 8.6)

Follow the order of operations (PEMDAS).

4.4+(56+8.6)

4.4+(64.6)

answer: 69

6 0
3 years ago
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find the elasped time from 10:11 to 5:34 pls show your work . A) 5hrs and 37mins , B) 4hrs , C) 5h 23mins , D) 4hr 37mins
Bingel [31]
The question as you wrote it doesn't fit the answers. However, one of the answers fits if you meant
"elapsed time from 5:34 to 10:11".

There are many ways to do this. Try first taking the time from 5:34 to 6:11, and after that finding the time from 6:11 to to 10:11.

In a way, 6:00 is the same thing as 5:60. Add 11 to that and you can see that 6:11 is the same as 5:71. Now that you have an easy way to find the time from 5:34 to 6:11.
6:11 - 5:34 isn't easy.
But 5:71 - 5:34 is quite easy. 71 - 34 is 37.

So, from 5:34 to 6:11 there are 37 minutes.

Now the easy part, finding the time from 6:11 to 10:11. Since the minutes are the same, just subtract the hours. 10 - 6 = 4 hours.

Now you have the hours and minutes, which number 4 hours and 37 minutes.
8 0
3 years ago
Luiza is jumping on a trampoline.
lyudmila [28]

Answer:

The second time when Luiza reaches a height of 1.2 m = 2 08 s

Step-by-step explanation:

Complete Question

Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.

H(t) = -0.6 cos (2pi/2.5)t + 1.5.

What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.

Solution

Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as

H(t) = -0.6cos⁡(2π/2.5)t + 1.5

What is t when H = 1.2 m

1.2 = -0.6cos⁡(2π/2.5)t + 1.5

0.6cos⁡(2π/2.5)t = 1.2 - 1.5 = -0.3

Cos (2π/2.5)t = (0.3/0.6) = 0.5

Note that in radians,

Cos (π/3) = 0.5

This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,

Cos (5π/3) = 0.5

So,

Cos (2π/2.5)t = Cos (5π/3)

(2π/2.5)t = (5π/3)

(2/2.5) × t = (5/3)

t = (5/3) × (2.5/2) = 2.0833333 = 2.08 s to the neareast hundredth of a second.

Hope this Helps!!!

4 0
3 years ago
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