(Eight thousandths) * thirty five million =
two hundred eighty thousand
Answer: Tyler used the distributive property.
Step-by-step explanation:
For the expression:
Madison wrote: which is by commutative property of addition.
The commutative property of addition says that , for a,b be any real number
Tyler wrote: which is by distributive propery.
The distributive property says that , for a,b,c be any real numbers.
Hence, the last option is correct.
4.4 + (4 × 14 + 8.6)
Follow the order of operations (PEMDAS).
4.4+(56+8.6)
4.4+(64.6)
answer: 69
The question as you wrote it doesn't fit the answers. However, one of the answers fits if you meant
"elapsed time from 5:34 to 10:11".
There are many ways to do this. Try first taking the time from 5:34 to 6:11, and after that finding the time from 6:11 to to 10:11.
In a way, 6:00 is the same thing as 5:60. Add 11 to that and you can see that 6:11 is the same as 5:71. Now that you have an easy way to find the time from 5:34 to 6:11.
6:11 - 5:34 isn't easy.
But 5:71 - 5:34 is quite easy. 71 - 34 is 37.
So, from 5:34 to 6:11 there are 37 minutes.
Now the easy part, finding the time from 6:11 to 10:11. Since the minutes are the same, just subtract the hours. 10 - 6 = 4 hours.
Now you have the hours and minutes, which number 4 hours and 37 minutes.
Answer:
The second time when Luiza reaches a height of 1.2 m = 2 08 s
Step-by-step explanation:
Complete Question
Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.
H(t) = -0.6 cos (2pi/2.5)t + 1.5.
What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.
Solution
Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as
H(t) = -0.6cos(2π/2.5)t + 1.5
What is t when H = 1.2 m
1.2 = -0.6cos(2π/2.5)t + 1.5
0.6cos(2π/2.5)t = 1.2 - 1.5 = -0.3
Cos (2π/2.5)t = (0.3/0.6) = 0.5
Note that in radians,
Cos (π/3) = 0.5
This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,
Cos (5π/3) = 0.5
So,
Cos (2π/2.5)t = Cos (5π/3)
(2π/2.5)t = (5π/3)
(2/2.5) × t = (5/3)
t = (5/3) × (2.5/2) = 2.0833333 = 2.08 s to the neareast hundredth of a second.
Hope this Helps!!!
