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3 years ago

A student takes a 15 question

Mathematics

1 answer:

tensa zangetsu [6.8K]3 years ago

3 0

1/2^9 given that the first question is already known as correct

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Enter the statement, with the values in the same order, but with parentheses so that the statement is true. 9 × 4 − 4 × 5 + 12 ÷

Sever21 [200]

9(4-4) x (5+12)/4=28

6 0

3 years ago

This season, Lisa's lacrosse team has won $\frac 23 of their home games (games played at Lisa's school), but just $\frac 25 of t

juin [17]

Answer:

Lisa's team have played 24 home games and 25 away games.

Step-by-step explanation:

Given:

Let $x$ represents games played at home.

also $y$ represent games played away.

Total number of games played = 49

∴ $x+y=49 \ \ \ \ equation \ 1$

Now according to given data:

Number of home games won = $\frac{2}{3}$

Number of away game won = $\frac{2}{5}$

Total games won =26

Hence

$\frac{2}{3}x+\frac{2}{5}y=26\\\\\frac{2\times 5}{3\times 5}x+\frac{2\times 3}{5\times 5}y=26\\\\\frac{10}{15}x+\frac{6}{15}y=26\\\\\frac{10x+6y}{15}=26\\\\10x+6y= 26\times 15\\10x+6y = 390\\2(5x+3y)=390\\5x+3y=\frac{390}{5}\\\\5x+3y=195 \ \ \ \ equation \ 2\\$

Now multiplying equation 1 by 3 we get,

$3(x+y)=3\times49\\3x+3y=147 \ \ \ \ \ equation \ 3\\$

Now Subtracting equation 2 by equation 3 we get,

$(5x+3y=195)-(3x+3y=147)\\2x=48\\x= \frac{48}{2}=24$

Substituting value of x in equation 1 we get.

$x+y=49\\24+y=49\\y=49-24=25$

Hence Lisa's team have played 24 home games and 25 away games.

3 0

3 years ago

At one farmer’s market, bananas cost $0.80 per pound. At another farmer’s market, bananas are sold in 5-pound bags for $4.50 per

Tems11 [23]

Hey I just need points

6 0

3 years ago

Read 2 more answers

What is the slope of the line represented by the equation y =4/3x-3

LekaFEV [45]

Answer:

m, is equal to (4/3)

Step-by-step explanation:

Match the given equation y =(4/3)x-3 to the standard slope-intercept form y = mx + b. By doing so we see that the slope, m, is equal to (4/3).

3 0

3 years ago

If the basalt at the top of the ancient valley below Vulcan's Throne yields a radiometric date (K-Ar) of 15,000 years, and the l

zepelin [54]

Answer:

$1.69\times 10^3$ feet/million year

Step-by-step explanation:

We are given that

Elevation of top of basalt in valley =4100 feet

Elevation of bottom of basalt in valley =2100 feet

Age of top of basalt in valley=15000 years

Age of bottom of basalt in valley=1.2 million years= $1.2\times 10^6 years=1200000 years$

We have to find the rate of basalt filling in the valley in feet per million yeas

Rate of basalt filling in the valley= $\frac{Elevation\;of\;top\;of\;basalt\;in\;valley-elevation\;of\;bottom\;of\;basalt\;in\;valley}{age\;of\;bottom\;of\;basalt\;in\;valley-age\;of\;top\;of\;basalt\;in\;valley}$

Rate of basalt filling in the valley= $\frac{4100-2100}{1200000-15000}=\frac{2000}{1185000}=1.69\times 10^{-3} feet/year$

Rate of basalt filling in the valley= $1.69\times 10^{-3}\times 10^{6}=1.69\times 10^3$ feet/million year

6 0

4 years ago