All categories

2 years ago

HELP

Mathematics

2 answers:

chubhunter [2.5K]2 years ago

8 0

The net represents a cube.

The net shows a cube with a side length of 12 cm, meaning its surface area is $6(12)^{2}=\boxed{864 \text{ cm}^{3}}$

yKpoI14uk [10]2 years ago

6 0

Answer:

cube
864 cm²

Step-by-step explanation:

The Platonic solid with six (6) square faces is the cube. Its surface area is the sum of the areas of the square faces. Each of those is the square of its edge length.

The 3-dimensional shape represented by the net is a cube.

The area of the cube is ...

6 × (12 cm)² = 6 × (144 cm²) = 864 cm²

You might be interested in

PLEASE HELP! URGENT!

TEA [102]

Answer:

C, I believe!

7 0

3 years ago

Read 2 more answers

Jeremy lost his dog, and wants to make some signs to put up in the neighborhood. The cost to make 8 paper signs and 2 laminated

Mashcka [7]

Answer:

cost to make paper signs = $1

cost to make laminated signs = $2

Step-by-step explanation:

Let

x = cost to make paper signs

y = cost to make laminated signs

8x + 2y = 12 (1)

10x + 10y = 30 (2)

Multiply (1) by 5

40x + 10y = 60 (3)

10x + 10y = 30 (2)

Subtract (2) from (3) to solve for x

40x - 10x = 60 - 30

30x = 30

x = 30/30

x = $1

Substitute x = 1 into (1)

8x + 2y = 12

8(1) + 2y = 12

8 + 2y = 12

2y = 12 - 8

2y = 4

y = 4/2

y = $2

cost to make paper signs = $1

cost to make laminated signs = $2

5 0

3 years ago

A proper fraction is converted to a decimal equivalent by dividing the denominator into the numerator. True

kondaur [170]

False, it's the other way around: you divide the numerator by the denominator.

For example, to evaluate $\frac{8}{15}$ you divide 8 by 15:

$\dfrac{8}{15} = 8\div 15 = 0.5\overline{3}$

7 0

3 years ago

A sample of 81 account balances of a credit company showed an average balance of $1,200 with a standard deviation of $126.

TEA [102]

Answer:

(a) Null Hypothesis, $H_0$ : $\mu$ = $1,150

Alternate Hypothesis, $H_A$ : $\mu$ $\neq$ $1,150

(b) The test statistic is 3.571.

(c) We conclude that the mean of all account balances is significantly different from $1,150.

Step-by-step explanation:

We are given that a sample of 81 account balances of a credit company showed an average balance of $1,200 with a standard deviation of $126.

We have test the hypothesis to determine whether the mean of all account balances is significantly different from $1,150.

Let $\mu$ = mean of all account balances

(a)So, Null Hypothesis, $H_0$ : $\mu$ = $1,150 {means that the mean of all account balances is equal to $1,150}

Alternate Hypothesis, $H_A$ : $\mu$ $\neq$ $1,150 {means that the mean of all account balances is significantly different from $1,150}

The test statistics that will be used here is One-sample t test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average balance = $1,200

s = sample standard deviation = $126

n = sample of account balances = 81

(b) So, test statistics = $\frac{1,200-1,150}{\frac{126}{\sqrt{81} } }$ ~ $t_8_0$

= 3.571

The value of the sample test statistics is 3.571.

(c) Now, P-value of the test statistics is given by the following formula;

P-value = P( $t_8_0$ > 3.571) = Less than 0.05%

Because in the t table the highest critical value for t at 80 degree of freedom is given between 3.460 and 3.373 at 0.05% level.

Now, since P-value is less than the level of significance as 5% > 0.05%, so we sufficient evidence to reject our null hypothesis.

Therefore, we conclude that the mean of all account balances is significantly different from $1,150.

8 0

3 years ago

Which equation is equivalent to

Anton [14]

Answer:

$m { }^{2} + 3m + 2 = 0$

Step-by-step explanation:

ну где-то тааакккккккккк

8 0

3 years ago