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dezoksy [38]
3 years ago
9

Can you solve -3(y-5)=24

Mathematics
2 answers:
garri49 [273]3 years ago
7 0

Answer:y=-3

Step-by-step explanation:yes firs multiply everything by -3 in parenthesies

Then you would subtract 15 from both sides

Next you would divide 9 by -3 and you would get -3

So y =-3

KengaRu [80]3 years ago
4 0
-3(y-5)=24
Distribute the -3 with the equation in the parentheses
-3y+15=24
Then take away the 15 from itself and 15 away from 24
-3y=9
Then you divide 9 by -3 which is -3.
y=-3
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Write an algebraic expression for each statement:
Andrei [34K]

For the given sentences, the algebraic expressions are:

a) N = 110*c - 300

b) N = 12*b

<h3>How to get the algebraic expressions?</h3>

For the first statement:

A 3-digit number, where the tens digit is c, can be written as:

N = 100*a + 10*c + b

Then the hundreds digit is a, and here we know that is 3 less than the tens digit, then:

a = c - 3

The ones digit is b, here we know that it is 0, then b = 0.

Replacing that in our number we get:

N = 100*(c - 3) + 10*c = 110*c - 300

N = 110*c - 300

That is the algebraic expression.

b) A two-digit number can be written as:

N = b*10 + a

Where b is the tens digit and a is the ones digit.

Here we know that the units digit is twice as bit as the tens digit, then:

a = 2b

Replacing that we get:

N = b*10 + a = b*10 + 2b = 12*b

N = 12*b

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4 0
2 years ago
Find the value of x. if your answer is not an interger, leave it in simplest radical form. The diagram is not drawn to scale. PL
Reptile [31]
Just do pythagorean theorem. The answer is the square root of 75
8 0
3 years ago
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The mean time it takes to walk to the bus stop is 8 minutes (with a standard deviation of 2 minutes) and the mean time it takes
11111nata11111 [884]
(a) Average time to get to school
Average time (minutes) = Summation of the two means = mean time to walk to bus stop + mean time for the bust to get to school = 8+20 = 28 minutes

(b) Standard deviation of the whole trip to school
Standard deviation for the whole trip = Sqrt (Summation of variances)

Variance = Standard deviation ^2
Therefore,
Standard deviation for the whole trip = Sqrt (2^2+4^2) = Sqrt (20) = 4.47 minutes

(c) Probability that it will take more than 30 minutes to get to school
P(x>30) = 1-P(x=30)
Z(x=30) = (mean-30)/SD = (28-30)/4.47 ≈ -0.45
Now, P(x=30) = P(Z=-0.45) = 0.3264
Therefore,
P(X>30) = 1-P(X=30) = 1-0.3264 = 0.6736 = 67.36%

With actual average time to walk to the bus stop being 10 minutes;

(d) Average time to get to school
Actual average time to get to school = 10+20 = 30 minutes

(e) Standard deviation to get to school
Actual standard deviation = Previous standard deviation = 4.47 minutes. This is due to the fact that there are no changes with individual standard deviations.

(f) Probability that it will take more than 30 minutes to get to school
Z(x=30) = (mean - 30)/Sd = (30-30)/4.47 = 0/4.47 = 0

From Z table, P(x=30) = 0.5
And therefore, P(x>30) = 1- P(X=30) = 1- P(Z=0.0) = 1-0.5 = 0.5 = 50%
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3 years ago
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Answer:

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3 years ago
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uysha [10]

We can solve this using substitution.

because x-y=2.5

x=y+2.5

Now substitute x into other equation.

2(y+2.5)^2-2y=125

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2y^2+8y-112.5=0

Now comes the ugly part

y=-4+-sqrt(16+900)

y=-4+-sqrt916

y=-4+-2sqrt229

x=-1.5+-2sqrt229

6 0
3 years ago
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