For the given sentences, the algebraic expressions are:
a) N = 110*c - 300
b) N = 12*b
<h3>
How to get the algebraic expressions?</h3>
For the first statement:
A 3-digit number, where the tens digit is c, can be written as:
N = 100*a + 10*c + b
Then the hundreds digit is a, and here we know that is 3 less than the tens digit, then:
a = c - 3
The ones digit is b, here we know that it is 0, then b = 0.
Replacing that in our number we get:
N = 100*(c - 3) + 10*c = 110*c - 300
N = 110*c - 300
That is the algebraic expression.
b) A two-digit number can be written as:
N = b*10 + a
Where b is the tens digit and a is the ones digit.
Here we know that the units digit is twice as bit as the tens digit, then:
a = 2b
Replacing that we get:
N = b*10 + a = b*10 + 2b = 12*b
N = 12*b
That is the algebraic expression.
If you want to learn more about algebraic expressions:
brainly.com/question/4541471
#SPJ1
Just do pythagorean theorem. The answer is the square root of 75
(a) Average time to get to school
Average time (minutes) = Summation of the two means = mean time to walk to bus stop + mean time for the bust to get to school = 8+20 = 28 minutes
(b) Standard deviation of the whole trip to school
Standard deviation for the whole trip = Sqrt (Summation of variances)
Variance = Standard deviation ^2
Therefore,
Standard deviation for the whole trip = Sqrt (2^2+4^2) = Sqrt (20) = 4.47 minutes
(c) Probability that it will take more than 30 minutes to get to school
P(x>30) = 1-P(x=30)
Z(x=30) = (mean-30)/SD = (28-30)/4.47 ≈ -0.45
Now, P(x=30) = P(Z=-0.45) = 0.3264
Therefore,
P(X>30) = 1-P(X=30) = 1-0.3264 = 0.6736 = 67.36%
With actual average time to walk to the bus stop being 10 minutes;
(d) Average time to get to school
Actual average time to get to school = 10+20 = 30 minutes
(e) Standard deviation to get to school
Actual standard deviation = Previous standard deviation = 4.47 minutes. This is due to the fact that there are no changes with individual standard deviations.
(f) Probability that it will take more than 30 minutes to get to school
Z(x=30) = (mean - 30)/Sd = (30-30)/4.47 = 0/4.47 = 0
From Z table, P(x=30) = 0.5
And therefore, P(x>30) = 1- P(X=30) = 1- P(Z=0.0) = 1-0.5 = 0.5 = 50%
Answer:
43cm
Step-by-step explanation:
96-10 (5 x2 sides)=86
86/2 sides=43 longest side
We can solve this using substitution.
because x-y=2.5
x=y+2.5
Now substitute x into other equation.
2(y+2.5)^2-2y=125
2y^2+10y+12.5-2y=125
2y^2+8y-112.5=0
Now comes the ugly part
y=-4+-sqrt(16+900)
y=-4+-sqrt916
y=-4+-2sqrt229
x=-1.5+-2sqrt229