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2 years ago

2

Mathematics

1 answer:

andreev551 [17]2 years ago

4 0

Answer:

Step-by-step explanation:

The line is going through the lower numbers for price but the higher numbers of pounds of apples.

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Please help find Sin(A)

kodGreya [7K]

Answer:

sinA=p/h

sinA=32/40=4/5

5 0

3 years ago

I neeeeddddd helppppp !!!!! It’s urgenttttttt

baherus [9]

х=10

I'm so sorry, i don't know how it's called (because English isn't my native language) but there are angles that have the same value

maybe u'll tell me..

3 0

3 years ago

(easy points)

Pepsi [2]

Answer:

April

Step-by-step explanation:

If you add 12 months it will be November once more. Then add 5 months which is April.

6 0

3 years ago

A cone frustum is inscribed in a sphere of radius 13. If one of the bases of the frustum is a great circle of the sphere, and th

Rudik [331]

Answer:

Step-by-step explanation:

According to the question, A cone frustum is inscribed in a sphere of radius 13. If one of the bases of the frustum is a great circle of the sphere, and the other base has radius 12.We are now asked to find the height of the frustum.

---The height of this frustum is equal to the distance of its smaller base from the center of the sphere.

Therefore,it is assigned the pattern

H = √(r1² - r2²

Where r1 is the radius of the sphere

And r2 is the radius of the other base of the frustum

H is the height that we are looking for

H = √(13² - 12²)

= √( 169 - 144 )

= √ 25

H = 5

5 0

3 years ago

Use Stokes' Theorem to calculate the circulation of the field F around the curve C in the indicated direction. F = 3yi + yj+zk

jok3333 [9.3K]

Answer:

$\int \int \bigtriangledown F\ X\ dS = \int F\cdot dr$ = 12π

Step-by-step explanation:

The field F is given by:

$F = 3y\hat{i} + y\hat{j}+z\hat{k}$ (1)

The curve C is the ellipse:

$\frac{x^2}{4}+\frac{y^2}{64}=1\\\\(\frac{x}{2})^2+(\frac{y}{8})^2=1$

In order to calculate the circulation of F around the curve C, you first find the parametric equation for the given ellipse.

The general form of an ellipse equation is:

$(\frac{x}{a})^2+(\frac{y}{b})^2=1$

The parametric equation is:

$r(t)=acost \hat{i} + bsint\hat{j}=2cost\hat{i}+8sint\hat{j}$ (2)

The Stokes's theorem is given by the following identity:

$\int \int \bigtriangledown F\ X\ dS = \int F\cdot dr$

The path integral is also:

$\int F\cdot dr=\int F(r(t))\cdot dr(t)$ (3)

For F(r(t)) and dr(t) you obtain:

$F(r(t))=3(8sint)\hat{j}+(8sint)\hat{j}+(z)\hat{k}\\\\dr(t)=(-2sint\hat{i}+8cost\hat{j}+0\hat{k})dt\\\\F(r(t))\cdot dr(t)=(-48sin^2t+64cos^2t)dt$

Next, in the equation (3) you obtain:

$\int_0^{2\pi} (-48sin^2t+64cos^2t)dt=\int_0^{2\pi}(-\frac{48}{2}(1-cos2t)+\frac{64}{2}(1+cos2t))dt\\\\=\int_0^{2\pi}(-24+24cos2t+32+32cos2t)dt\\\\=\int_0^{2\pi}(6+56cos2t)dt\\\\=[6t+56sin2t]_0^{2\pi}=[6(2\pi)-0]=12\pi$

The circulation of the field around C is 12π

5 0

3 years ago