х=10
I'm so sorry, i don't know how it's called (because English isn't my native language) but there are angles that have the same value
maybe u'll tell me..
Answer:
April
Step-by-step explanation:
If you add 12 months it will be November once more. Then add 5 months which is April.
Answer:
5
Step-by-step explanation:
According to the question, A cone frustum is inscribed in a sphere of radius 13. If one of the bases of the frustum is a great circle of the sphere, and the other base has radius 12.We are now asked to find the height of the frustum.
---The height of this frustum is equal to the distance of its smaller base from the center of the sphere.
Therefore,it is assigned the pattern
H = √(r1² - r2²
Where r1 is the radius of the sphere
And r2 is the radius of the other base of the frustum
H is the height that we are looking for
H = √(13² - 12²)
= √( 169 - 144 )
= √ 25
H = 5
Answer:
= 12π
Step-by-step explanation:
The field F is given by:
(1)
The curve C is the ellipse:

In order to calculate the circulation of F around the curve C, you first find the parametric equation for the given ellipse.
The general form of an ellipse equation is:

The parametric equation is:
(2)
The Stokes's theorem is given by the following identity:
The path integral is also:
(3)
For F(r(t)) and dr(t) you obtain:

Next, in the equation (3) you obtain:
![\int_0^{2\pi} (-48sin^2t+64cos^2t)dt=\int_0^{2\pi}(-\frac{48}{2}(1-cos2t)+\frac{64}{2}(1+cos2t))dt\\\\=\int_0^{2\pi}(-24+24cos2t+32+32cos2t)dt\\\\=\int_0^{2\pi}(6+56cos2t)dt\\\\=[6t+56sin2t]_0^{2\pi}=[6(2\pi)-0]=12\pi](https://tex.z-dn.net/?f=%5Cint_0%5E%7B2%5Cpi%7D%20%28-48sin%5E2t%2B64cos%5E2t%29dt%3D%5Cint_0%5E%7B2%5Cpi%7D%28-%5Cfrac%7B48%7D%7B2%7D%281-cos2t%29%2B%5Cfrac%7B64%7D%7B2%7D%281%2Bcos2t%29%29dt%5C%5C%5C%5C%3D%5Cint_0%5E%7B2%5Cpi%7D%28-24%2B24cos2t%2B32%2B32cos2t%29dt%5C%5C%5C%5C%3D%5Cint_0%5E%7B2%5Cpi%7D%286%2B56cos2t%29dt%5C%5C%5C%5C%3D%5B6t%2B56sin2t%5D_0%5E%7B2%5Cpi%7D%3D%5B6%282%5Cpi%29-0%5D%3D12%5Cpi)
The circulation of the field around C is 12π