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2 years ago

What is the surface area of the prism below?

Mathematics

2 answers:

jeyben [28]2 years ago

8 0

I will answer in one second

myrzilka [38]2 years ago

4 0

Answer:

63 m²

Step-by-step explanation:

added in the picture

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Am I right or wrong if so please tell me the answer

PolarNik [594]

Answer: I believe you are correct I got the same answer as you.

8 0

3 years ago

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A college professor never finishes his lecture before the end of the hour and always finishes his lectures within 2 min after th

Citrus2011 [14]

Answer:

Value of k is $\displaystyle\frac{3}{8}$

Step-by-step explanation:

We are given the following information in the question:

$f(x) = kx^2, 0\leq x \leq 2\\~~~~~~~= 0, \text{ otherwise}$

where x is the time elapses between the end of the hour and the end of the lecture.

We have to find the values of k.

Since, f(x) is the pdf, then,

$\displaystyle\int^\infty_{-\infty} f(x) = 1\\\\\displaystyle\int^2_{0} f(x) = 1\\\\\displaystyle\int^2_{0} kx^2 = 1\\\\k\bigg[\frac{x^3}{3}\bigg]^2_0 = 1\\\\k\times \frac{8}{3} = 1\\\\k = \frac{3}{8}$

Hence, value of k is $\displaystyle\frac{3}{8}$

4 0

2 years ago

A new car depreciates 11% per year. if the new car is worth 23,882 today how much will it worth in 4 years

Andrei [34K]

Answer:

Well..

Step-by-step explanation:

Do 23,882 by 11, then do the answer of that problem divided by 11 and so on

8 0

3 years ago

Pleaseeeee answer I will mark brainliest for best answer ^>^

Orlov [11]

Answer: 7.6

Explanation:

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3 years ago

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Consider a game in which a participant pays $2 to roll a die. The participant receives $3 if they roll a 1 (i.E. They go up by a

Sauron [17]

Answer:

The expected monetary value of a single roll is $1.17.

Step-by-step explanation:

The sample space of rolling a die is:

S = {1, 2, 3, 4, 5 and 6}

The probability of rolling any of the six numbers is same, i.e.

P (1) = P (2) = P (3) = P (4) = P (5) = P (6) = $\frac{1}{6}$

The expected pay for rolling the numbers are as follows:

E (X = 1) = $3

E (X = 2) = $0

E (X = 3) = $0

E (X = 4) = $0

E (X = 5) = $0

E (X = 6) = $4

The expected value of an experiment is:

$E(X)=\sum x\cdot P(X=x)$

Compute the expected monetary value of a single roll as follows:

$E(X)=\sum x\cdot P(X=x)\\=[E(X=1)\times \frac{1}{6}]+[E(X=2)\times \frac{1}{6}]+[E(X=3)\times \frac{1}{6}]\\+[E(X=4)\times \frac{1}{6}]+[E(X=5)\times \frac{1}{6}]+[E(X=6)\times \frac{1}{6}]\\=[3\times \frac{1}{6}]+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]\\+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]+[4\times \frac{1}{6}]\\=1.17$

Thus, the expected monetary value of a single roll is $1.17.

7 0

3 years ago