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3 years ago

Find the Sum: (20 - 6) + 3(c + 8)

Mathematics

1 answer:

RideAnS [48]3 years ago

6 0

Answer:

38 + 3c

Step-by-step explanation:

Apply the distributed property: (20 - 6) + 3c + 24
20 - 6 = 14
Plug 14 in: 14 + 3c + 24
Combine like terms: 38 + 3c

I hope this helps!

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Contact [7]

The rate of change is ur slope.

The table : company p
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y/x = 6/100 = 0.06

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3 years ago

Pls help answer this

Paladinen [302]

Answer: Third option

Step-by-step explanation:

For this exercise it is important to remember the following:

1. By definition, the Associative property of addition states that it does not matter how you grouped the numbers, you will always obtained the same sum.

2. The rule for the Associative property of addition is the following (given three numbers "a", "b" and "c"):

$a + (b + c) = (a + b) + c$

Knowing the information shown before, you can identify in the picture attached that the option that illustrates the Associative property of addition is the third one. This is:

$(11+8)+1=11+(8+1)$

As you can notice that you will always get the same result:

$(19)+1=11+(9)\\\\20=20$

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3 years ago

3 x 4 1/3 = ??<br><br><br> -- please help me

andrezito [222]

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3 years ago

3³ - (4)(2) find da value or die mwaha

eduard

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3 years ago

Which statement describes the inverse of m(x) = x^2 – 17x?

DochEvi [55]

Given:

The function is

$m(x)=x^2-17x$

To find:

The inverse of the given function.

Solution:

We have,

$m(x)=x^2-17x$

Substitute m(x)=y.

$y=x^2-17x$

Interchange x and y.

$x=y^2-17y$

Add square of half of coefficient of y , i.e., $\left(\dfrac{-17}{2}\right)^2$ on both sides,

$x+\left(\dfrac{-17}{2}\right)^2=y^2-17y+\left(\dfrac{-17}{2}\right)^2$

$x+\left(\dfrac{17}{2}\right)^2=y^2-17y+\left(\dfrac{17}{2}\right)^2$

$x+\left(\dfrac{17}{2}\right)^2=\left(y-\dfrac{17}{2}\right)^2$ $[\because (a-b)^2=a^2-2ab+b^2]$

Taking square root on both sides.

$\sqrt{x+\left(\dfrac{17}{2}\right)^2}=y-\dfrac{17}{2}$

Add $\dfrac{17}{2}$ on both sides.

$\sqrt{x+\left(\dfrac{17}{2}\right)^2}+\dfrac{17}{2}=y$

Substitute $y=m^{-1}(x)$ .

$m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}$

We know that, negative term inside the root is not real number. So,

$x+\left(\dfrac{17}{2}\right)^2\geq 0$

$x\geq -\left(\dfrac{17}{2}\right)^2$

Therefore, the restricted domain is $x\geq -\left(\dfrac{17}{2}\right)^2$ and the inverse function is $m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}$ .

Hence, option D is correct.

Note: In all the options square of $\dfrac{17}{2}$ is missing in restricted domain.

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3 years ago