Answer:
20 is 80% of 25
Step-by-step explanation:
We assume, that the number 25 is 100% - because it's the output value of the task.
2. We assume, that x is the value we are looking for.
3. If 100% equals 25, so we can write it down as 100%=25.
4. We know, that x% equals 20 of the output value, so we can write it down as x%=20.
5. Now we have two simple equations:
1) 100%=25
2) x%=20
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
100%/x%=25/20
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.
7. Solution for 20 is what percent of 25
100%/x%=25/20
(100/x)*x=(25/20)*x - we multiply both sides of the equation by x
100=1.25*x - we divide both sides of the equation by (1.25) to get x
100/1.25=x
80=x
x=80
640 x 0.30= 192
640-192= 448
448 is the answer
Answer:
Juan imprimió 7 páginas a color.
Step-by-step explanation:
Llamemos "b" a las copias en blanco y negro y "c" a las copias en color.
Juan imprimió 75 páginas. En forma simbólica es:
b + c = 75
b = 75 - c [1]
El costo de impresión de cada página en una biblioteca es de 5 centavos si es en blanco y negro o 50 centavos si es a color. En total pago $6.90. En forma simbólica es:
0.05b + 0.5c = 6.90 [2]
Si reemplazamos [1] en [2],
0.05(75-c) + 0.5c = 6.90
3.75 - 0.05c + 0.5c = 6.90
0.45c = 3.15
c = 7
Juan imprimió 7 páginas a color.
Answer:
the answer is 15 subtract the highest number from the lowest
Answer:
The coordinates of ABCD after the reflection across the x-axis would become:
Step-by-step explanation:
The rule of reflection implies that when we reflect a point, let say P(x, y), is reflected across the x-axis:
- x-coordinate of the point does not change, but
- y-coordinate of the point changes its sign
In other words:
The point P(x, y) after reflection across x-axis would be P'(x, -y)
P(x, y) → P'(x, -y)
Given the diagram, the points of the figure ABCD after the reflection across the x-axis would be as follows:
P(x, y) → P'(x, -y)
A(2, 3) → A'(2, -3)
B(5, 5) → B'(5, -5)
C(7, 3) → C'(7, -3)
D(5, 2) → D'(5, -2)
Therefore, the coordinates of ABCD after the reflection across the x-axis would become:
