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2 years ago

Evaluate the following expression. (-3)-² =

Mathematics

1 answer:

Viktor [21]2 years ago

7 0

Answer:

The answer to this is 9.

Step-by-step explanation:

First of all, you wrote the expression wrong, but that's okay. It's supposed to be written as (-3)².

Second of all, since multiplying two negatives makes a positive and squaring is just multiplying the integer to itself, then -3×-3=9. I hope this helps! :)

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Solve for : 3 2 + −10 = 0. PLEASE HELP

Snezhnost [94]

Answer:

Step-by-step explanation:

32+(-10)

32-10

22 is not equal to 0

so its false

7 0

3 years ago

Read 2 more answers

Adam spent $3.42 on orange juice. It costs .12 per ounce. How many did Adam buy?

SIZIF [17.4K]

Hi,

I would say that the answer is 28, but it still doesn't add up because when you multiply 12 by 28 you get $3.36 which isn't enough to meet his total, so I tried multiplying 12 by 29 and I got $3.48, which is six cents over his total. So I'm sorry if it is wrong I tried to help to my best ability.

I hope it helps, have a great day/night!!!

5 0

3 years ago

Simplify the following expression. 3 2/5x3(-7/5)

Studentka2010 [4]

The simplified expression of 32/5 x 3(-7/5) is -672/25

<h3>How to simplify the expression?</h3>

The mathematical expression is given as:

32/5 x 3(-7/5)

Evaluate the product of 3 and -7/5

32/5 x 3(-7/5) = 32/5 x -21/5

Evaluate the product of 32 and -21

32/5 x 3(-7/5) = 672/5 x -1/5

Evaluate the product of 5 and 5

32/5 x 3(-7/5) = 672/25 x -1

So, we have:

32/5 x 3(-7/5) = -672/25

Hence, the simplified expression of 32/5 x 3(-7/5) is -672/25

Read more about expressions at:

brainly.com/question/723406

#SPJ1

8 0

2 years ago

What fraction of the dunk tanks require at least 500 gallons of water? Write the fraction in simplest form.

Cerrena [4.2K]

Answer:

1/2

Step-by-step explanation:

Based on the information observed from the attached box and whisker plot, the Fraction of dunk tanks which requires atleast 500 gallons of water. This fractional value will be the property of plot in the position marked as 500 on the plot. The point which refers to 500 gallons on the plot is the ticked point in between the box. This point represents the median value in a box and whisker plot.

The median value represents the 50th percentile value which relates to half of the distribution. This means that fraction of dunk which requires atleast 500 gallons is : (50/100) = 1/2

7 0

3 years ago

First question, thanks. I believe there should be 3 answers

zysi [14]

Given: The following functions

$A)cos^2\theta=sin^2\theta-1$ $B)sin\theta=\frac{1}{csc\theta}$ $\begin{gathered} C)sec\theta=\frac{1}{cot\theta} \\ D)cot\theta=\frac{cos\theta}{sin\theta} \\ E)1+cot^2\theta=csc^2\theta \end{gathered}$

To Determine: The trigonometry identities given in the functions

Solution

Verify each of the given function

$\begin{gathered} cos^2\theta=sin^2\theta-1 \\ Note\text{ that} \\ sin^2\theta+cos^2\theta=1 \\ cos^2\theta=1-sin^2\theta \\ Therefore \\ cos^2\theta sin^2\theta-1,NOT\text{ }IDENTITIES \end{gathered}$

$\begin{gathered} sin\theta=\frac{1}{csc\theta} \\ Note\text{ that} \\ csc\theta=\frac{1}{sin\theta} \\ sin\theta\times csc\theta=1 \\ sin\theta=\frac{1}{csc\theta} \\ Therefore \\ sin\theta=\frac{1}{csc\theta},is\text{ an identities} \end{gathered}$

$\begin{gathered} sec\theta=\frac{1}{cot\theta} \\ note\text{ that} \\ cot\theta=\frac{1}{tan\theta} \\ tan\theta cot\theta=1 \\ tan\theta=\frac{1}{cot\theta} \\ Therefore, \\ sec\theta\ne\frac{1}{cot\theta},NOT\text{ IDENTITY} \end{gathered}$

$\begin{gathered} cot\theta=\frac{cos\theta}{sin\theta} \\ Note\text{ that} \\ cot\theta=\frac{1}{tan\theta} \\ cot\theta=1\div tan\theta \\ tan\theta=\frac{sin\theta}{cos\theta} \\ So, \\ cot\theta=1\div\frac{sin\theta}{cos\theta} \\ cot\theta=1\times\frac{cos\theta}{sin\theta} \\ cot\theta=\frac{cos\theta}{sin\theta} \\ Therefore \\ cot\theta=\frac{cos\theta}{sin\theta},is\text{ an Identity} \end{gathered}$

$\begin{gathered} 1+cot^2\theta=csc^2\theta \\ csc^2\theta-cot^2\theta=1 \\ csc^2\theta=\frac{1}{sin^2\theta} \\ cot^2\theta=\frac{cos^2\theta}{sin^2\theta} \\ So, \\ \frac{1}{sin^2\theta}-\frac{cos^2\theta}{sin^2\theta} \\ \frac{1-cos^2\theta}{sin^2\theta} \\ Note, \\ cos^2\theta+sin^2\theta=1 \\ sin^2\theta=1-cos^2\theta \\ So, \\ \frac{1-cos^2\theta}{sin^2\theta}=\frac{sin^2\theta}{sin^2\theta}=1 \\ Therefore \\ 1+cot^2\theta=csc^2\theta,\text{ is an Identity} \end{gathered}$

Hence, the following are identities

$\begin{gathered} B)sin\theta=\frac{1}{csc\theta} \\ D)cot\theta=\frac{cos\theta}{sin\theta} \\ E)1+cot^2\theta=csc^2\theta \end{gathered}$

The marked are the trigonometric identities

3 0

2 years ago