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3 years ago

Find the area and the circumference of a circle with diameter 4 ft

Mathematics

1 answer:

GenaCL600 [577]3 years ago

5 0

Answer:

Circumference is 12.56

Area is 6.28

Step-by-step explanation:

4×3.14=12.56

2×3.14=6.28

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Pls answer asap 7 - 3 r = r - 4 ( 2 + r)

Marianna [84]

Answer:

no real answer

Step-by-step explanation:

distribute the -4 and combine all of the like terms on the left side = r-8-4r, then -8-3r

then we have 7-3r=-8-3r

from here, we can already tell that there's no real answer. this is because the two -3r will cancel, leaving no variable.

since 7 doesn't equal -8, there is no answer.

if, for example, the value on both sides of the equal sign were the same after the variable was eliminated, then your answer would be all real numbers

8 0

2 years ago

Kelly and 23 friends go roller skating they pay a total of $186 about how much does it cost for one person to skate hhhhhheeeeee

n200080 [17]

You need to figure out the unit rate so you need to:
1. divide 186 by 23= 8.08695....
2. You only need to figure out the answer to the hundredth of a percent so you would round and get $8.09
3. The answer is $8.09

8 0

3 years ago

Read 2 more answers

What is algebra in 5th grade

katrin [286]

Fifth grade algebra<span> and functions worksheets contain math problems with variables.</span>

6 0

3 years ago

Read 2 more answers

For each of the following functions, determine if they are injective. Also determine if theyare surjective. Also determine if th

timurjin [86]

Answer:

Check below

Step-by-step explanation:

1. Definition for intervals

$(a,b)=\left \{ x\in\Re : a$

2. Functions

1) $\Re \rightarrow \Re \\ f(x)=x$

Let's perform graph tests.

That's an one to one, injective function. Look how any horizontal line touches that only once. Also, It's a surjective and a bijective one.

2) $\Re\geq0\rightarrow\Re , f(x)=x+1\\$

Injective, surjective and bijective.

Injective: a horizontal line crosses the graph in one point.

3) $f:\Re\geq 0\rightarrow\Re, f(x) = cos(x)$

The cosine function is not injective, bijective nor surjective.

4) $f:\Re\rightarrow\Re \:f(x)=ex$

Since e, is euler number it's a constant. It's also injective, surjective and bijective.

5) Quite unclear format

$6) \:f:\Re\rightarrow(0,\infty), f(x) =ex$

Despite the Restriction for the CoDomain, the function remains injective, surjective and therefore bijective.

$7) f:\Re\geq 0 \rightarrow \Re\geq0, f(x) =x^{4}$

Not injective nor surjective therefore not bijective too.

$8).f:\{-1,2,-3\}}\rightarrow \{1,4,9\}, f(x) =x^{2}$

$f(-1)=1, f(2)=4, f(-3)=9$

Injective (one to one), Surjective, and Bijective.

$10) f:\Re\geq 0\rightarrow [-1,1], f(x)= cos(x)\\-1=cos(x) \therefore x=\pi,3\pi,5\pi,etc.$

Surjective.

$11.f:R\geq 0[-1,1], f(x) = 0\\$

Surjective

12.f: US Citizens→Z, f(x) = the SSN of x.

General function

13.f: US Zip Codes→US States, f(x) = The state that x belongs to.

Surjective

7 0

3 years ago

What are the answers to these questions? 3 questions, 100 points.

emmasim [6.3K]

Answer for LCD of fractions 5/6 and 3/8: 24

Step-by-step explanation:

5/6 and 3/8 - Get the multiples of 6: 6, 12, 18, 24, Multiples of 8: 8, 16, 24, 32.

The LEAST common one you can find is 24.

Answer for LCD of fractions 1/2 and 3/5: 10, or C

This one is a bit easier - just find multiples of 5 that are even. The least one is 10.

Answer for LCD of fractions 1/12 and 3/4: 12, or B

Explanation: Multiples of 12 that are multiples of 4 but the least of them: 12.

6 0

1 year ago