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Tju [1.3M]
2 years ago
7

Solve (x - 2 < 5) ∩ (x + 7 > 6).

Mathematics
1 answer:
hoa [83]2 years ago
7 0

Answer:

c2

Step-by-step explanation:

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Anybody know how to answer this? Explain if you can, please :)
garik1379 [7]
Carrie is 2 and Kim is just born.
you can have,

Carrie = 3      4     5     6
    Kim = 1      2     3     4

Or something like that, thats a table btw

5 0
4 years ago
Roger’s father knows that Dial It Up sells data plans at $16 for 2 gigabytes and Ring Ring sells data plans at $9 for 1 gigabyte
Juli2301 [7.4K]

Answer:

dial it up

2:16

simplify

1:8

now multiply 8 by the number of gigs

2:16

3:24

and so on.....

ring ring

1:9

again multiply the cost by the number of gigs

2:18

3:27

and so on....

8 0
3 years ago
WILL GIVE BRAINLIEST TO PERSON WHO ANSWERS CORRECTLY!!!!!
MAVERICK [17]
7 < x. Here, you can solve the inequality by multiplying 2 by each quantity in the parentheses to get -18 < 24 - 6x. You can subtract -24 from both sides to get -42 < -6x. Then, you can divide each side by -6 and flip the inequality, and this leaves you with x > 7. You would check this answer by choosing a number greater than but close to 7, using the original equation. 
3 0
3 years ago
Use the given conditions to write an equation in slope-intercept form. slope = -5, passing through (-4,2) My suggestion is to fi
Brut [27]

Answer:

<h2>y = -5x -18</h2>

Step-by-step explanation:

Plug-in values in point -slope form ;

y -y_1=m(x-x_1)\\y - 2 =-5(x-(-4))\\y-2 = -5(x+4)\\y-2 =-5x -20\\y = -5x -20+2\\y = -5x -18

3 0
4 years ago
The figure below shows a square ABCD and an equilateral triangle DPC:
Allisa [31]

Answer:

Which of the following completes Ted's proof?

In square ABCD; angle ADC = angle BCD

In square ABCD; angle ADP = angle BCP

In triangles APD and BPC; angle ADC = angle BCD

In triangles APD and BPC; angle ADP = angle BCP\

7 0
2 years ago
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