The system of inequalities is: and
<em><u>Explanation</u></em>
Let be the amount of live bait and
be the amount of natural bait.
As John would like to get at least 3 pounds of live bait, so the first inequality will be:
Given that, price of live bait is $12 per pound and natural bait is $7 per pound. Also, he only has a budget of $63. That means, he can spend maximum $63
So, the cost for buying pound of live bait
and the cost for buying
pound of natural bait
Thus, the second inequality will be:
Hi there!
We can create an equation for the line PR using the given coordinates. Use the following formula for the slope:
Plug in the coordinates for P and R:
Find the equation by using point-slope form:
y - y1 = m(x - x1)
Plug in a coordinate and the slope:
y - (-5) = -4/3(x - ( - 1))
Simplify:
y + 5 = -4/3(x + 1)
To find the y-coordinate if x = 2, plug in the x value:
y + 5 = -4/3(2 + 1)
y + 5 = -4/3(3)
y + 5 = -4
y = -9
Thus, the coordinate is (2, -9)
Answer:
Part A
The bearing of the point 'R' from 'S' is 225°
Part B
The bearing from R to Q is approximately 293.2°
Step-by-step explanation:
The location of the point 'Q' = 35 km due East of P
The location of the point 'S' = 15 km due West of P
The location of the 'R' = 15 km due south of 'P'
Part A
To work out the distance from 'R' to 'S', we note that the points 'R', 'S', and 'P' form a right triangle, therefore, given that the legs RP and SP are at right angles (point 'S' is due west and point 'R' is due south), we have that the side RS is the hypotenuse side and ∠RPS = 90° and given that =
, the right triangle ΔRPS is an isosceles right triangle
∴ ∠PRS = ∠PSR = 45°
The bearing of the point 'R' from 'S' measured from the north of 'R' = 180° + 45° = 225°
Part B
∠PRQ = arctan(35/15) ≈ 66.8°
Therefore the bearing from R to Q = 270 + 90 - 66.8 ≈ 293.2°
