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Sveta_85 [38]
3 years ago
7

Write 720 as a product of its prime factors

Mathematics
2 answers:
alexgriva [62]3 years ago
7 0
<span>720 = 2^4 * 3² * 5
does this help </span>
vlada-n [284]3 years ago
3 0
Prime factors are natural numbers that has no divisors except 1 and itself as 2,3,5,7 and many many more
so, you need to use this numbers to do a prime factorization.
So, the prime factorization of 720 is 2^4 * 3^2 * 5
Hope this Helps :D
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Please help with A, B, and C
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Which of the following random variables should be considered continuous? Select one: a. The number of cars owned by a randomly c
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3 0
1 year ago
11. Let f(x) = 2x² + 7x + 5
Lady_Fox [76]

Answer:

(x+1)(2x+5)

Step-by-step explanation:

f(x) = 2x² + 7x + 5

Factor the expression by grouping. First, the expression needs to be rewritten as 2x²+ax+bx+5. To find a and b, set up a system to be solved.

a+b=7

ab=2×5=10

Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 10.

1,10

2,5

Calculate the sum for each pair.

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The solution is the pair that gives sum 7.

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2x²+7x+5 as (2x²+2x)+(5x+5).

(2x²+2x)+(5x+5)

Factor out 2x in the first and 5 in the second group.

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Factor out common term x+1 by using distributive property.

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