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expeople1 [14]
2 years ago
14

What is the area of a regular hexagon with an apothem 18.5 inches long and a side 21 inches

Mathematics
1 answer:
earnstyle [38]2 years ago
3 0

The area of a regular hexagon with an apothem 18.5 inches long and a side 21 inches is 1, 165. 5 In²

<h3>How to calculate the area of a regular hexagon</h3>

The formula is given thus;

Area of hexagon = (1/2) × a × P

where a = the length of the apothem

P = perimeter of the hexagon

Given a = 18. 5 inches

Note that Perimeter, p = 6a with 'a' as side

p = 6 × 21 = 126 inches

Substitute values into the formula

Area, A = 1 ÷2 × 18. 5 × 126 = 1 ÷2 × 2331 = 1, 165. 5 In²

Thus, the area of the regular hexagon is 1, 165. 5 In²

Learn more about the area of a hexagon here:

brainly.com/question/15424654

#SPJ1

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Show calculations for each of the ratio table
Sladkaya [172]

Answer:

From left to right:

3, 30, 20

Step-by-step explanation:

Start by determining the ratio of yellow to red paint. Use the column where both amounts are given:

yellow to red = 2 to 6 = 1 to 3

2 to 6 the same as 1 to 3 when reduced, by dividing both sides by 2.

This means yellow paint is a third of red paint. Backwards, red paint is three times yellow paint.

To go from yellow to red, do yellow X 3.

To go from red to yellow, do red ÷ 3.

Column 1:

1 X 3 = 3

Column 3:

10 X 3 = 30

Column 4:

60 ÷ 3 = 20

The ratios are:

1 to 3

2 to 6

10 to 30

20 to 60

4 0
4 years ago
Which shapes have at least one pair of parallel sides?
elena-s [515]
Parallelograms and trapezoids always do.

(Note:  "Parallelograms" includes rectangles, squares, and rhombussesses.)

Any polygon with more than 4 sides <u>can</u> have at least one pair of parallel sides,
but it's not guaranteed.
3 0
3 years ago
(W+4)(3w-2) please solveeed
Shkiper50 [21]

Step-by-step explanation:

{:}\longrightarrow\sf (w+4)(3w-2)

{:}\longrightarrow\sf w(3w-2)+4 (3w-2)

{:}\longrightarrow\sf 3w^2-2w+12w-8

{:}\longrightarrow\sf 3w^2+10w-8

7 0
3 years ago
Read 2 more answers
I really need help on this question
statuscvo [17]

Answer:

its the third one

Step-by-step explanation:

3 0
3 years ago
Joe earns $14 an hour and Blaine earns $18 per hour. Joe receives a raise of $1.75 every six months, and Blaine receives a raise
Katarina [22]

After 4 interval of six months, Joe to earn same hourly rate as Blaine

<em><u>Solution:</u></em>

Given that,

Amount earned by Joe = $ 14 per hour

Amount earned by Blaine = $ 18 per hour

Lets assume the number of six month intervals be "x"

<em><u>Joe receives a raise of $1.75 every six months</u></em>

Therefore,

Joe earning: 14 + 1.75(number of six month intervals)

Equation for Joe earning: 14 + 1.75x ------- eqn 1

<em><u>Blaine receives a raise of $0.75 every six months</u></em>

Therefore,

Blaine earning: 18 + 0.75(number of six month intervals)

Equation for Blaine earning: 18 + 0.75x ------------ eqn 2

The number of six-month intervals it will take Joe to earn the same hourly rate as Blaine,

Eqn 1 must be equal to eqn 2

14+1.75x = 18+0.75x\\\\1.75x-0.75x = 18-14\\\\1x = 4\\\\x = 4

Thus after 4 interval of six months, Joe to earn same hourly rate as Blaine.

8 0
4 years ago
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