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irina1246 [14]
2 years ago
15

how do the chromosomes contained in a gamete differ from the chromosomes contained in other normal human cells?

Biology
1 answer:
CaHeK987 [17]2 years ago
3 0

Gametes have 23 chromosomes, while other normal human cells have 46 chromosomes.

<h3>What is chromosome?</h3>

Chromosomes are threadlike structures made of protein and a single molecule of DNA that serve to carry the genomic information from cell to cell.

<h3>Difference between chromosomes in gamete and normal human</h3>

Gametes have 23 chromosomes, while other normal human cells have 46 chromosomes.

Learn more about chromosome here: brainly.com/question/11912112

#SPJ11

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What results from meiosis of a diploid cell? ​
Korolek [52]

Answer:

Meiosis is a type of cell division that reduces the number of chromosomes in the parent cell by half and produces four gamete cells. The process results in four daughter cells that are haploid, which means they contain half the number of chromosomes of the diploid parent cell

Explanation:

Meiosis begins with a parent cell that is diploid, meaning it has two copies of each chromosome. ... The process results in four daughter cells that are haploid, which means they contain half the number of chromosomes of the diploid parent cell.

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3 years ago
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What happens in meiosis I that does not occur in meiosis II?
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5 0
3 years ago
If the frequency of an allele is 0.75, how many copies of this allele should be in a population of 300 diploid individuals?
Ray Of Light [21]

I have provided the options below:

a. 150

b. 225

c. 300

d. 450

e. 75

Answer:

150

Explanation:

Hardy-Weinberg law states, the allelic frequencies of a gene that is, q and p follow the relationship p^2+q^2+2pq = 1, if the population is in equilibrium.

Therefore p^2+q^2+2pq = 1, can be used to calculate the percentage of the allelic frequencies i.e. p^2 and q^2

Allelic frequency = 0.75.

Therefore, the percentage of the allele in the population would be given by

0.75^2 = 0.5625 = 56%.

And the total number of individuals with this allele in the population:

number of individuals = 56×300÷100

= 168 or

150 nearest figure.

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