Answer:
is a linear m=4 y=3
Step-by-step explanation:
Answer: (-2, 0) and (0, -2)
Step-by-step explanation:
This system is:
y + x = -2
y = (x + 1)^2 - 3
To solve this we first need to isolate one of the variables in one fo the equations, in the second equation we have already isolated the variable y, so we can just replace it in the first equation:
(x + 1)^2 - 3 + x = -2
Now we can solve this for x.
x^2 + 2*x + 1 - 3 = -2
x^2 + 2*x + 1 -3 + 2 = 0
x^2 + 2*x + 0 = 0
The solutions of this equation are given by the Bhaskara's formula, then the solutions are:
The two solutions are:
x = (-2 - 2)/2 = -2
In this case, we replace this value of x in the first equation and get:
y - 2 = -2
y = -2 + 2 = 4
This solution is x = -2, y = 0, or (-2, 0)
The other solution for x is:
x = (-2 + 2)/2 = 0
If we replace this in the first equation we get:
y + 0 = -2
y = -2
This solution is x = 0, y = -2, or (0, -2)
No there could be a repeating bar over two meaning that it will keep the same number
Answer:
30,000,000 + 400,000 + 50,000 + 9,000 + 800 + 70
Step-by-step explanation:
Not many steps, just typing it out.
30,000,000 + 400,000 + 50,000 + 9,000 + 800 + 70
(edit: thank you for Brainliest!)
We are asked to find the positive angle that is co-terminal to 132°.
We know that co-terminal angles are angles who share the same initial side and terminal sides.
To find the positive angle that is co-terminal to 132°, we will add 360 degrees to 132°.
Therefore, the positive angle that is co-terminal to 132 degrees is 492 degree and option A is the correct choice.