The answer is -51, hope this helps
        
                    
             
        
        
        
Answer:
   40 mph
Step-by-step explanation:
We assume "outbound" refers to the trip <em>to the lake</em>. The ratio of speeds is inversely proportional to the ratio of times, so ...
   outbound speed : inbound speed = 4 : 3
These differ by one ratio unit, so that one ratio unit corresponds to the speed difference of 10 mph. Then the 4 ratio units of outbound speed will correspond to ...
   4×10 mph = 40 mph
Paul's average speed on the outbound trip was 40 mph.
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The distance to the lake was 120 mi.
 
        
                    
             
        
        
        
Answer:
11
Step-by-step explanation:
 
        
                    
             
        
        
        
Given:
ABCD is a quadrilateral
AC = 12, DE = 4 and FB = 5
To find:
The area of the polygon.
Solution:
AC bisects the quadrilateral into two triangles.
Area of triangle:

<u>Area of triangle DAC:</u>



Area of triangle DAC = 24 square units.
<u>Area of triangle BAC:</u>



Area of triangle BAC = 30 square units.
Area of polygon = Area of triangle DAC + Area of triangle BAC
                            = 24 square units + 30 square units
                            = 54 square units
The area of the polygon is 54 square units.