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Hatshy [7]
1 year ago
11

At the movie theatre, child admission is 6.30 and adult admission is 9.50 . On Sunday, four times as many adult tickets as child

tickets were sold, for a total sales of 1063.20 . How many child tickets were sold that day?
Mathematics
1 answer:
Lady_Fox [76]1 year ago
4 0

According to the characteristics of <em>ticket</em> sales and the resulting system of linear equations we find that 122 children bought each one a ticket on Sunday.

<h3>How many children went to the movie theatre?</h3>

In this question we have a <em>word</em> problem, whose information must be translated into <em>algebraic</em> expressions to find a solution. Let be x and y the number of children and adults that went to the movie theatre, respectively.

We need two <em>linear</em> equations, one for the number of people assisting to the theatre and another for the total sales:

x - 4 · y = 0     (1)

6.30 · x + 9.50 · y = 1063.20     (2)

By algebraic procedures the solution to this system is: x = 122.559, y = 30.639. Since the number of tickets sold are integers, then we truncate each result: x = 122, y = 30.

According to the characteristics of <em>ticket</em> sales and the resulting system of linear equations we find that 122 children bought each one a ticket on Sunday.

To learn on systems of linear equations: brainly.com/question/27664510

#SPJ1

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If the first term of AP is 4 and the sum of first five term is equal to one-fourth of the sum of the next five term, then find t
patriot [66]

Answer:

15th term = 116

Step-by-step explanation:

a= 4

Sum of an A.P = n/2 {2a + (n-1)d}

sum of first five term is equal to one-fourth of the sum of the next five term

5/2{ 2*4 + (5-1)d} = 1/4 × 10/2{2*4 + (10-1)d

5/2 {8 + 4d} = 1/4 × 5{ 8 + 9d}

40/2 + 20/2d = 1/4{ 40 + 45d)

20 + 10d= 40/4 + 45/4d

20 + 10d = 10 + 45/4d

20 - 10 = 45/4d - 10d

10 =45d - 40d /4

10 = 5/4d

Divide both sides by 5/4

10 ÷5/4 = d

10×4/5 = d

40/5 = d

8 = d

d= 8

Find the 15th term

15th term = a + (n-1)d

= 4 + (15-1)8

= 4 + (14)8

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The 15th term is 116

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3 years ago
A science class has 5 girls and 7 boys in the seventh grade and 5 girls and 5 boys in the eighth grade. The teacher randomly sel
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A ladder 10 m long,leans against a vertical wall at an angle of 70° to the ground.if the ladder slips down the wall 4m,find,corr
lina2011 [118]

Answer:

(a) the new angle the ladder makes with the ground is 32.7^o

(b) the ladder slipped back about 5 meters

Step-by-step explanation:

Notice that the ladder doesn't change its length in the process.

So let's start from the initial situation , finding the distance from the ground at which the ladder touches the wall when the angle with the ground is 70^o. Notice that this situation is represented by a right angle triangle with the right angle between the wall and the ground (see attached image), and that we can use the sine function to find the side opposite to the 70 degree angle:

sin(70^o)=\frac{opposite}{hypotenuse} \\sin(70^o)=\frac{h}{10}\\h=10\, sin(70^o) \approx 9.4 \,\,m

therefore 9.4 meters is approximately the height at which the ladder touches the wall initially.

Now, if the tip of the ladder goes down the wall 4 meters, it is now at 9.4 m - 4 m = 5.4 m from the ground. We can therefore use again the sine function to solve for the new angle:

sin(x)=\frac{opposite}{hypotenuse} \\sin(x)=\frac{5.4}{10} \\sin(x)=0.54\\x=arcsin(0.54)\\x= 32.7^o

To answer the second question we need to find the original distance from the wall that the bottom of the ladder was originally, and for that we can use the cosine function:

cos(70^o)=\frac{adjacent}{hypotenuse} \\cos(70^o)=\frac{x}{10}\\x=10\,cos(70^o)\\x\approx 3.4  \,\,m

Now fro the new position of the bottom of the ladder relative to the wall:

cos(32.7^o)=\frac{adjacent}{10} \\adjacent=10\,cos(32.7^o)\\adjacent\approx 8.4\,\,m

then the difference in between those two distances is what we need:

8.4 m - 3.4 m = 5 m

4 0
3 years ago
What is the solution to this system of linear equations?
LekaFEV [45]

Answer:

4th

Step-by-step explanation:

(-1,3)

here is the answer

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astraxan [27]

Answer:

B

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∠ ABC = 0.5( 82 + 44)° = 0.5 × 126° = 63° → B

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