You need to draw the triangle DEF with a right angle at E. Angle D = 40 and DE = 100 m. Once you have marked up your triangle, you can use cosine to find DF.
well 3x15= 45 and 15x17= 255 so 45+255= 300
They all end up being 1
100% = 1
4/4 = 1
1.000 = 1
Answer:
Let P be the external point. O be the origin. join O and P get OP and nearest point on the circle from P be A.
Let Q be the point onthe circle in which, tangent make 90° with radius at Q.
PQ = 8 and OQ = 6
we get a right angled triangle PQO right angled at Q.
so, OP^2 = OQ^2 + PQ^2= 8^2 + 6^2 = 64 + 36 =1==
therefore OP =10cm
we need nearest point from P, which is PA
PA = OP - OA= 10 -6=4cm
Answer:
a number line that goes from 0 to 16. the whiskers range from 1 to 12, and the box ranges from 3 to 9. a line divides the box at 7.