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Lady bird [3.3K]
2 years ago
10

What values for theta (0≤theta≤2π) satisfy the equation?

Mathematics
1 answer:
Talja [164]2 years ago
7 0

The values for θ (0 ≤ θ ≤ 2π) that satisfy the equation are; D: θ = π/3, 5π/3

<h3>How to simplify trigonometric equations?</h3>

We are given the trigonometric equation;

3 sin θ = sin θ - √3

Rearranging this gives;

sin θ - 3 sin θ = √3

(1 - 3) sin θ = √3

-2sin θ = √3

sin θ = -(√3)/2

θ = sin⁻¹-(√3)/2

θ = π/3, 5π/3

Read more about Trigonometric Equations at; brainly.com/question/24349828

#SPJ1

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