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maria [59]
3 years ago
14

The area of a circle is 4π ft². What is the circumference, in feet? Express your answer in terms of \piπ.

Mathematics
2 answers:
Gnesinka [82]3 years ago
7 0

Answer:2 ft

Step-by-step explanation:

Area of circle = pi x r^2 = 4 pi

So r^2 = 4

r =2

sweet [91]3 years ago
4 0

Answer:

4π m

Step-by-step explanation:

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Answer:

-<u>One Equation</u>: is set equal to a variable

Example:

y = 2x + 1

x + 3y = -12

You already have y, plug it back into x + 3y = -12

x + 3(2x + 1) = -12

x + 6x + 3 = -12

7x + 3 = -12

(Subtract 3 from each side)

7x = -15

(Divide by 7)

x = - 2.14

-<u>No Equation</u>: is set equal to a variable

Example:

2x + y = 10

4× + 2y = -3

Subtract 2x from each side of 2x + y = 10, you should get y= -2x + 10. Now that you have found y, substitute y into 4x+ 2y = -3.

4x + 2(-2x + 10) = -3

4x + -4x + 20 = -3

(Subtract 20 from each side)

4x + -4x = -23

(Add 4x and -4x)

0 = -23

No Solution

<u>-Both</u><u> </u><u>Equations</u>: are set equal to a variable

Example:

y = x + 5

y = -x + 3

(you already have y so plug it into the other equation to solve for x)

-x + 3 = x + 5

(Add -x on both sides)

3 = 2x + 5

(subtract 5 from both sides)

-2 = 2x

(Divide by 2 on each side)

x = -1

I hope this helped!

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2 years ago
Margaret is saveing money for her sumergido vacation. Se calculates herstarting a Out is 0.4% of her total amount she wants to s
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I need help please...
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What percentage of the semi circle is shaded? <br>​
mezya [45]

The percentage of the semicircle shaded section is approximately 23,606 %.

The percentage of the area of the semicircle is equal to the ratio of the semicircle area minus the half-cross area to the semicircle area. In other words, we have the following expression:

r = \left(\frac{A_{s}-A_{h}}{A_{s}} \right)\times 100\,\%

r = \left(1-\frac{A_{h}}{A_{s}} \right)\times 100\,\% (1)

Where:

  • A_{h} - Area of the half cross, in square centimeters.
  • A_{s} - Area of the semicircle, in square centimeters.
  • r - Percentage of the shaded section of the semicircle.

And the percentage of the shaded section is:

r = \left[1-\frac{4 \cdot (2\,cm)^{2}+4\cdot \left(\frac{1}{2} \right)\cdot (2\,cm)^{2}}{0.5\cdot \pi\cdot (16\,cm^{2}+4\,cm^{2})} \right]\times 100

r \approx 23.606\,\%

The percentage of the semicircle shaded section is approximately 23,606 %.

We kindly invite to check this question on percentages: brainly.com/question/15469506

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What is 679 rounded to the nearest ten
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680 is the answer to that question
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2 years ago
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