Answer:
Distance = 10 km
Step-by-step explanation:
Let x be the number of hours taken from school to town and y be the number of hours taken back to the school
Then distance covered during first trip would be 10x (distance = speed*time) and during the second trip would be 8y. Both distances are equal.
=> 10x = 8y
Dividing both sides by 2
=> 5x = 4y
=> 5x-4y = 0 ------------------(1)
<u><em>The total time for both the trips is:</em></u>
=> x + y = 2.25 -------------------(2)
Multiplying eq (2) by 5
=> 5x+5y = 11.25 ---------------(3)
Subtacting (3) from (1)
=> 5x-4y-5x-5y = 0-11.25
=> -4y-5y = -11.25
=> -9y = -11.25
Dividing both sides by -9
=> y = 1.25 hrs
Putting in (2)
=> x + 1.25 = 2.25
=> x = 2.25 - 1.25
=> x = 1 hr
<u><em>Now, Calculating the Distance</em></u>
=> Distance = 10x
=> 10 ( 1 )
=> Distance = 10 km
9514 1404 393
Answer:
- k = 45 . . . miles per hour
- k = 1/45 . . . hours per mile
Step-by-step explanation:
One way we can relate distance and time is ...
time = k × distance
Then the value of k (the constant of proportionality) is ...
k = time/distance = 4 hours/(180 miles)
k = (1/45) hours/mile
__
Another way we can relate the variables is ...
distance = k × time
Then the value of k (the constant of proportionality) is ...
k = distance/time = (180 miles)/(4 hours)
k = 45 miles/hour
I think equilateral and equiangular
each interval represents 1 unit
Answer:
option 4 is right
Step-by-step explanation:
Consider the trignometric function y =cotx
Since cot x has sin x in denominator, cot x is undefined whenever sinx =0
OR whenever x =n π, for any integer n, cot x is undefined
Hence domain =(-∞,∞) ,x≠nπ
Range = -∞<y<∞
since cotx can take any real values
The graph y=cotx will be a periodic function discontinuous at all integral multiples of pi and undefined for integral multiples of pi.
It is not defined for x=0 also
It passes through (pi/4,1) (npi/2,0)
i.e. x intercepts are odd multiples of pi/2
and it takes value 1 for pi/4, 5pi/4, .....
