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3 years ago

Helppp pls ASAP, I need to know what the y intercept is?!?!

Mathematics

1 answer:

Paladinen [302]3 years ago

8 0

Answer:

-1

Step-by-step explanation:

Y-intercept is the point in a graph where its (0,?). In your graph one box down is where that point is.

I hope this helped and if it did I would appreciate it if you marked me Brainliest. Thank you and have a nice day!

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On a test, Sarah got 48 questions correct out of 50. What percent did she get on her test?

photoshop1234 [79]

Answer:

96%

Step-by-step explanation:

48 / 50 = 0.96

0.96 x 100% = 96%

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3 years ago

Read 2 more answers

What is the range of y=10x

shutvik [7]

The answer is all real numbers.

5 0

3 years ago

dem82 [27]

Answer:

y = 2x - 19

Step-by-step explanation:

Slope-intercept form: y = mx + b

y = (x , y) = 1

m = slope = 2

x = (x , y) = 10

b = y-intercept

Plug in the corresponding numbers to the corresponding variables:

1 = 2(10) + b

First, simplify, and then isolate the variable, b. Note the equal sign, what you do to one side, you do to the other.

First, multiply 2 with 10:

1 = (2 * 10) + b

1 = 20 + b

Next, subtract 20 from both sides of the equation:

1 = b + 20

1 (-20) = b + 20 (-20)

1 - 20 = b

b = -19

Plug in 2 for m, and -19 for b.

y = 2x - 19 is your slope-intercept form.

8 0

3 years ago

The third term of an arithmetic sequence is 21, and the eighth term is 56. The first term is _____.

aleksley [76]

The first term is 7. This is because the sequence has a pattern of increasing by 7. If the first term was 7, the second would be 14, the third would be 21. The 4th would be 28, continue to the 8th term 56.

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3 years ago

Which of the following is not one of the 8th roots of unity?

Anika [276]

Answer:

1+i

Step-by-step explanation:

To find the 8th roots of unity, you have to find the trigonometric form of unity.

1. Since $z=1=1+0\cdot i,$ then

$Rez=1,\\ \\Im z=0$

and

$|z|=\sqrt{1^2+0^2}=1,\\ \\\\\cos\varphi =\dfrac{Rez}{|z|}=\dfrac{1}{1}=1,\\ \\\sin\varphi =\dfrac{Imz}{|z|}=\dfrac{0}{1}=0.$

This gives you $\varphi=0.$

Thus,

$z=1\cdot(\cos 0+i\sin 0).$

2. The 8th roots can be calculated using following formula:

$\sqrt[8]{z}=\{\sqrt[8]{|z|} (\cos\dfrac{\varphi+2\pi k}{8}+i\sin \dfrac{\varphi+2\pi k}{8}), k=0,\ 1,\dots,7\}.$

Now

at k=0, $z_0=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 0}{8}+i\sin \dfrac{0+2\pi \cdot 0}{8})=1\cdot (1+0\cdot i)=1;$

at k=1, $z_1=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 1}{8}+i\sin \dfrac{0+2\pi \cdot 1}{8})=1\cdot (\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2})=\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2};$

at k=2, $z_2=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 2}{8}+i\sin \dfrac{0+2\pi \cdot 2}{8})=1\cdot (0+1\cdot i)=i;$

at k=3, $z_3=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 3}{8}+i\sin \dfrac{0+2\pi \cdot 3}{8})=1\cdot (-\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2})=-\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2};$

at k=4, $z_4=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 4}{8}+i\sin \dfrac{0+2\pi \cdot 4}{8})=1\cdot (-1+0\cdot i)=-1;$

at k=5, $z_5=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 5}{8}+i\sin \dfrac{0+2\pi \cdot 5}{8})=1\cdot (-\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2})=-\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2};$

at k=6, $z_6=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 6}{8}+i\sin \dfrac{0+2\pi \cdot 6}{8})=1\cdot (0-1\cdot i)=-i;$

at k=7, $z_7=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 7}{8}+i\sin \dfrac{0+2\pi \cdot 7}{8})=1\cdot (\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2})=\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2};$

The 8th roots are

$\{1,\ \dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2},\ i, -\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2},\ -1, -\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2},\ -i,\ \dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2}\}.$

Option C is icncorrect.

5 0

3 years ago