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1 year ago

could someone help me solve this equations with both comparison and elimination methods: 2(x+y)=120 and 2(2x+y/3)=170

Mathematics

1 answer:

Gnom [1K]1 year ago

4 0

Answer:

y=21 X=39

Step-by-step explanation:

expand brackets on first equation: 2x+2y=120

now divide the second equation by 2 on both sides:

2x+y/3=85

then subtract the second equation from the first equation

so (2x+2y) - (2x+y/3)

the 2x on both sides cancel out and you get 5/3 y

this is equal to the sum of the first equation subtract the second equation which is 35

divide both sides by 5/3 and you get

y=21

substitute y in the first equation and you get X=39

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2 years ago

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Can y’all please helpppp!

Rudiy27

Answer:

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Step-by-step explanation:

1)As the triangles are similar, here the ratio is as;

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$\frac{DE}{HJ} = \frac{EF}{JG} = \frac{FD}{GH}$

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could someone help me solve this equations with both comparison and elimination methods: 2(x+y)=120 and 2(2x+y/3)=170​

could someone help me solve this equations with both comparison and elimination methods: 2(x+y)=120 and 2(2x+y/3)=170