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Maslowich
3 years ago
7

How many kilometers can that tortoise walk in 1 hour

Mathematics
1 answer:
vfiekz [6]3 years ago
6 0
5 kilometers

Jjjjjjkkkk
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Which of the following equations could be used to solve the given equation? 9x + 26 + 7x - 17 = 2x + (-3x) + 5x
gavmur [86]

\left(\mathrm{Decimal:\quad }x=-0.75\right)



hope it helps :P


4 0
3 years ago
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Susan went shopping to purchase new clothes. She
arlik [135]

Answer:

13.375

Step-by-step explanation:

you have to add 28 ± 17 = 45 ± 8.857 = 13.375

6 0
3 years ago
in a recent season NASCAR driver Jimmie Johnson won 6 of the 36 total races held to the nearest thousand ,find the part of races
castortr0y [4]
So, the fraction of races that he won was:

\frac{6}{36} : you need ti divide the number of occurrences by the number of possibilities.

We can simplify this:
\frac{1}{6}.

When we write it in decimals until the closest place, it's:

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5 0
3 years ago
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What are the two solutions of <br><br>2|2y-1| + 5 = 19​
Bess [88]

Answer:

y=4

y=−3

Step-by-step explanation:

8 0
3 years ago
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if we have a geometric series with u1 = 2.1 and r= 1.06, what would the least value of n be such that Sn &gt; 5543?
bulgar [2K]

Answer:

  88

Step-by-step explanation:

Write the expression for the sum in the relation you want.

  Sn = u1(r^n -1)/(r -1) = 2.1(1.06^n -1)/(1.06 -1)

  Sn = (2.1/0.06)(1.06^n -1) = 35(1.06^n -1)

The relation we want is ...

  Sn > 5543

  35(1.06^n -1) > 5543 . . . . substitute for Sn

  1.06^n -1 > 5543/35 . . . .  divide by 35

  1.06^n > 5578/35 . . . . . . add 1

  n·log(1.06) > log(5578/35) . . . take the log

  n > 87.03 . . . . . . . . . . . . . . divide by the coefficient of n

The least value of n such that Sn > 5543 is 88.

3 0
3 years ago
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