Ask question

Ask question

All categories

1 year ago

14

Pete, a professional bowler, is unhappy with any game below 200. Over time, 80% of his games exceed this score. What is the prob

ability that Pete exceeds 200 in at least 9 of his next 10 games?

1 answer:

Aneli [31]1 year ago

5 0

The probability that Pete exceeds 200 in at least 9 of his next 10 games is 0.268+0.1074 = 0.3754

<h3>What is Probability ?</h3>

Probability is defined as the likeliness of an event to happen.

It has a range of 0 to 1.

It is given that

Pete, a professional bowler, is unhappy with any game below 200

80% of his games exceed this score.

the probability that Pete exceeds 200 in at least 9 of his next 10 games is given by

P( 9/10 > 200) +P(10/10>200)

The binomial experiment consists of n trial out of it x is success.

$P( x) = \dfrac{n!}{x!(n-x)!}p^x(1-p)^{n-x}$

Here p = 0.8

For 9/10 matches

$P( 9/10 > 200) = \dfrac{10!}{9!(10-9)!}0.8^9(1-0.8)^{10-9}\\\\ = {10}(0.8)^9(0.2)\\= 0.268$

For (10/10 >200)

$P( 10/10 > 200) = \dfrac{10!}{10!(10-10)!}0.8^{10} (1-0.8)^{10-10}\\\\ = {1!}(0.8)^{10}\\= 0.1074$

Therefore the probability that Pete exceeds 200 in at least 9 of his next 10 games is 0.268+0.1074 = 0.3754.

To know more about Probability

brainly.com/question/11234923

#SPJ1

You might be interested in

I need help to Find the value of x. Round to<br> the nearest tenth.

Charra [1.4K]

Answer:

4.5

Step-by-step explanation:

We are given opposite and adjacent, so use tangent

tan(37)=x/6

6tan(37)=4.521324301

7 0

2 years ago

Find all degree solutions in the interval 0° ≤ θ < 360°. If rounding is necessary, round to the nearest tenth of a degree. Us

xenn [34]

Answer:

$\theta_{1} \approx 30.473^{\textdegree}$

$\theta_{2} \approx 120.473^{\textdegree}$

$\theta_{3} \approx 210.473^{\textdegree}$

$\theta_{4}\approx 300.473^{\textdegree}$

Step-by-step explanation:

The equation needs to be rearranged in terms of one trigonometric function:

$5\cdot \sin 2\theta - 9\cdot \cos 2\theta = 0$

$5\cdot \tan 2\theta - 9 = 0$

$5\cdot \tan 2\theta = 9$

$\tan 2\theta = \frac{9}{5}$

$\theta = \frac{1}{2}\cdot \tan^{-1} \left(\frac{9}{5} \right)$

The tangent function has positive values in the 1st and 3rd Quadrants. Then, the solutions are:

$\theta_{1} \approx 30.473^{\textdegree}$

$\theta_{2} \approx 120.473^{\textdegree}$

$\theta_{3} \approx 210.473^{\textdegree}$

$\theta_{4}\approx 300.473^{\textdegree}$

3 0

2 years ago

-4xy(4x2 + 7y - 8xy)

EastWind [94]

$- 4xy( {4x}^{2} + 7y - 8xy)$

$- 4xy( {4x}^{2} )- 4xy(7y)- 4xy( - 8xy)$

$- 16 {x}^{3} y - 28 {xy}^{2} + 32 {x}^{2} {y}^{2}$

4 0

2 years ago

You deposit $200 in an account earning 8% interest compounded annually. How much will you have in the account in 20 years?

Lynna [10]

You would have saved up $932, gaining a total of $732 saved in interests

4 0

2 years ago

Mark incorrectly solved the inequality -4(5/2+3/2x) > 8. His work is shown. Which step shows an error based on the inequality

aliya0001 [1]

Answer : The incorrect step is, (A) step 1: -10 + 6x > 8

Step-by-step explanation :

The given expression is:

$-4(\frac{5}{2}+\frac{3}{2}x)>8$

Now solving this expression step by step.

First -4 distributed over parentheses.

$(-4\times \frac{5}{2})+(-4\times \frac{3}{2}x)>8$

Now solving bracket term, we get:

$-10-6x>8$

Now taking like terms together, we get:

$-6x>8+10$

$-6x>18$

$-x>3$

Now multiplying this expression by (-1), we get:

$x>-3$

Thus, the incorrect step is, (A) step 1: -10 + 6x > 8

5 0

2 years ago