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Lisa [10]
3 years ago
5

It took a race car driver 3 hours and 15 minutes to go 500 miles. What was his mean rate of speed, to the nearest tenth of a mil

e per hour?
Apparently the answer is 153.8 mph, but I don’t know how to get the answer.
Mathematics
1 answer:
WINSTONCH [101]3 years ago
4 0
In order to calculate rate or average speed you divide miles by time

I got 153.8 by dividing 500 by 3.25 (the .25 is because 15 minutes is 1/4 of 60) hope this helped!!
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What is all the square numbers that are all greater than 20 but less than 50
Ede4ka [16]

Answer:

25, 36, 49

Step-by-step explanation:

I just listed them down since there aren't many.

1×1=2 (Smaller than 20)

2×2=4 (Smaller than 20)

3×3=9 (Smaller than 20)

4×4=16 (Smaller than 20)

5×5=25

6×6=36

7×7=49

8×8=64 (Bigger than 50)

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-a^2-a+12

Step-by-step explanation:

thats the product of (-a + 3)(a + 4)

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2 years ago
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b

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3 years ago
Find the rate of change of this line
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2 years ago
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erik [133]
2.=c.\\\\2\sin4x\cos4x=2\sin(2\cdot4x)=2\sin8x\\\\Used:\\\sin2\alpha=2\sin\alpha\cos\alpha

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3.=a.\\\\\dfrac{\sin x-1}{\sin x+1}=\dfrac{\sin x-1}{\sin x+1}\cdot\dfrac{\sin x+1}{\sin x+1}=\dfrac{\sin^2x-1^2}{(\sin x+1)^2}=\dfrac{\sin^2x-1}{(\sin x+1)^2}\\\\=\dfrac{-(1-\sin^2x)}{(\sin x+1)^2}=\dfrac{-\cos^2x}{(\sin x+1)^2}\\\\Used:\\(a-b)(a+b)=a^2-b^2\\\\\sin^2x+\cos^2x=1\to \cos^2x=1-\sin^2x
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3 years ago
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