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Mashutka [201]
2 years ago
8

Martin had 100 trees in his orchard the first year. Each year after that, he

Mathematics
2 answers:
alexgriva [62]2 years ago
7 0

Answer:

177

Step-by-step explanation:

This scenario can be modeled as an <u>exponential function</u>.

General form of an exponential function: y=ab^x

where:

  • a is the initial value (y-intercept)
  • b is the base (growth/decay factor) in decimal form
  • x is the independent variable
  • y is the dependent variable

If b > 1 then it is an increasing function

If 0 < b < 1 then it is a decreasing function

If the number of trees <u>increase</u> by <u>10% each year</u>, then the number of trees each year will be 110% of the number of trees the previous year.  Therefore, the <u>growth factor is 110%</u>.

Given:

  • a = 100 trees
  • b = 110% = 1.10 (in decimal form)
  • x = time (in years)
  • y = number of trees in the orchard

Substituting the given values into the function:

\implies y=100(1.10)^x

(where x is time in years and y is the number of trees in the orchard)

To find how many trees are in the orchard in the 6th year, input x = 6 into the found equation:

\implies 100(1.10)^6=177.1561=177\: \sf (nearest\:whole\:number)

Therefore, Martin had 177 trees in his orchard in the sixth year.

Akimi4 [234]2 years ago
6 0
  • Rate of increase=10%=0.1
  • Time=t=6

So trees after 1 year

  • 100+10=110

Trees after 2 years

  • 110+0.1(110)=121

Trees after 3 years

  • 121+0.1(121)
  • 133(Whole no)

Trees after 4years

  • 133+0.1(133)
  • 146

Trees after 5 years

  • 146+0.1(146)
  • 161

Trees after 6 years

  • 161+0.1(161)
  • 177trees
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