All categories

2 years ago

HEEELLLPPPP PLLLZZZ TT^TT

Mathematics

2 answers:

Sliva [168]2 years ago

5 0

The first one is 96 i think

Nuetrik [128]2 years ago

5 0

Answer:

1. 454

2. 96

Step-by-step explanation:

1. To find The surface area, find the are of each side. The bases of the triangular prism have the same surface area,

Surface area of triangle: 1/2b*h, half of the base times the height. base = 8, height = 10, 1/2(8) * 10 = 4*10 = 40, the other side has the same area, so double it to get 80.

The surface area of one of the rectangle is 11*14, another is 12*11, and the last is 11*8, multiply all to get 154, 132, and 88, and 154 + 132 + 88 + 80 = 454

2. The two triangles is 1/2b * h, b = 6, h = 2, 1/2(6) * 2 = 3*2 = 6, double it because there is another triangle to get 12

The three rectangles are 3*7 + 3*7 + 6*7 = 21 + 21 + 42 = 84, 84 + 12 = 96

You might be interested in

An oil drilling company is drilling a hole. The elevation of the bottom of the hole changes by feet each day. After a certain nu

marin [14]

Answer:

option.D

Step-by-step explanation:

each day it changes by $-73\frac{1}{4}$

so for two days , the elevation becomes $-73\frac{1}{4}$ + $-73\frac{1}{4}$

for 3 days : $-73\frac{1}{4}$ + $-73\frac{1}{4}$ + $-73\frac{1}{4}$

so, for n days, $-73\frac{1}{4}$ + ........ n times

= n* $-73\frac{1}{4}$

therefore, for x days, elevation = x* $-73\frac{1}{4}$

as it is given that after certain days this elevation has reached $-366\frac{1}{4}$

so, x* $-73\frac{1}{4}$ = $-366\frac{1}{4}$

3 0

2 years ago

Can some one please help me

Inessa05 [86]

Answer:

8:1

Step-by-step explanation:

Don reads 8 pages a minute. Therefore the amount of pages he could read is 8 and the amount of time it takes is a minute

7 0

2 years ago

Test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students at the 0.005 signif

algol [13]

Answer:

a) F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

b) B. two-tailed

d) $t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64$

e) $p_v =P(t_{118}$

f) B. Reject the null hypothesis

Step-by-step explanation:

Information provided

$\bar X_{O}=2.91$ represent the mean for the Orange Coast

$\bar X_{C}=2.96$ represent the mean for the Coastline

$s_{O}=0.05$ represent the sample standard deviation for Orange Coast

$s_{C}=0.03$ represent the sample standard deviation for Coastline

$n_{O}=60$ sample size for Orange Coast

$n_{C}=60$ sample size for Coastline

$\alpha=0.005$ Significance level provided

t would represent the statistic

Part a

For this case we want to test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students

Null hypothesis: $\mu_{O} \geq \mu_{C}$

Alternative hypothesis: $\mu_{O} < \mu_{C}$

F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

Part b

For this case we need to conduct a left tailed test.

B. two-tailed

Part d

The statistic is given by:

$t=\frac{(\bar X_{O}-\bar X_{C})-\Delta}{\sqrt{\frac{s^2_{O}}{n_{O}}+\frac{s^2_{C}}{n_{C}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=60+60-2=118$

Replacing the info we got:

$t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64$

Part e

We can calculate the p value with this probability:

$p_v =P(t_{118}$

Part f

Since the p value is a very low value compared to the significance level given of 0.005 we can reject the null hypothesis.

B. Reject the null hypothesis

5 0

2 years ago

X over 7+4 is greater than or equal to 16

Blizzard [7]

X/11>=16

X>=16x11

X>=176

5 0

2 years ago

Question 7. I need help in the answers for A.) and B.)

Ostrovityanka [42]

A=30+0.15t
B=30+0.15(200)=60

5 0

2 years ago

Read 2 more answers