Answer:
The last one.
Step-by-step explanation:
The standard form equation of an ellipse with foci on the y-axis is ...
y²/a² +x²/b² = 1
where "a" and "b" are the lengths of the semi-major and semi-minor axes, respectively. If "c" is the distance from the center to the focus, then this relation also holds:
b² +c² = a²
For this ellipse ...
b² + 8² = 17²
289 -64 = b² = 225 . . . . . subtract 8²
b = 15 . . . . . . . . . . . . . . . . . take the square root
The equation of the ellipse is then ...
y²/17² +x²/15² = 1
Answer:
x=4
Step-by-step explanation:
you subtract the x on both sides
6=2x-2
then you add 2 on both sides
8=2x
then divide 2 on both sides
and you get x=4
Answer: X = (
, 6)
Step-by-step explanation:
x(4x - 19) = 30
4x^2 - 19x = 30
4x^2 - 19x - 30 = 0
ax^2 + bx + c = 0
= 
= 6
=
= 
= -1.25
X = (, 6)
I would say that the answer is B
Let
be an integer. Suppose there is a triangle with legs of length 16 and
. Then by the Pythagorean theorem, the length of the hypotenuse should be
The formulas for Pythagorean triples say that if the legs are integers, then so must be the hypotenuse, because if
and
are integers, then so are
,
, and
.
However,
is not a perfect square trinomial, which means for any integer
, the length of the hypotenuse is not an integer, so such a triangle doesn't exist.
